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serg [7]
3 years ago
5

Which has a bigger surface area, powder or marble chips

Chemistry
1 answer:
kupik [55]3 years ago
4 0

Answer:

powder

Explanation:

Between the powder and marble chips, the powder will have a larger surface area.

For the same masses of a solid substance in different forms such as lump, granules or powder, the smaller particle size of each form the larger the surface area.

Surface area increases from lumps to granules and them powder

  • A powder has the largest surface area and hence undergoes a more faster chemical reaction.
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How many watts are required to power a guitar amplifier that operates on 220 volts and 22 amps?
VashaNatasha [74]
220 volt x 22 apms = 4840 watts
3 0
3 years ago
When 220 mL of 1.50x10^-4 M hydrochloric acid is added to 135 mL of 1.75x10^-4 M Mg(OH)2, the resulting solution will be________
siniylev [52]

Answer:

Basic

Explanation:

Considering

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

So,

Moles =Molarity \times {Volume\ of\ the\ solution}

For hydrochloric acid :

Molarity = 1.50\times 10^{-4} M

Volume = 220 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 220×10⁻³ L

Moles =1.50\times 10^{-4} \times {220\times 10^{-3}}\ moles

Moles of hydrochloric acid = 0.000033 moles

For Mg(OH)_2 :

Molarity = 1.75\times 10^{-4} M

Volume = 135 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 135×10⁻³ L

Moles =1.75\times 10^{-4} \times {135\times 10^{-3}}\ moles

Moles of Mg(OH)_2 = 0.000024 moles

According to the given reaction:

Mg(OH)_2_{(aq)}+2HCl_{(aq)}\rightarrow MgCl_2_{(s)}+2H_2O_{(aq)}

1 mole of Mg(OH)_2 reacts with 2 moles of HCl

Also,

0.000024 mole of Mg(OH)_2 reacts with 2*0.000024 moles of HCl

Moles of HCl = 0.000048 moles

Available moles of HCl = 0.000033 moles

Limiting reagent is the one which is present in small amount. Thus, HCl is limiting reagent.

Thus, HCL will be consumed completely and Mg(OH)_2 will be left over. Thus, the resulting solution will be basic.

4 0
4 years ago
Which shows an isomer of the molecule below?
babunello [35]
Above question is incomplete. Complete question is attached below
.......................................................................................................................

Correct Answer: Option D i.e. CH3CH2CH2CH2CH3

Reason:
Isomers are the compounds having same molecular formula, but different structural formula.

The molecular formula of the compound is C5H12

The compound present is question (i.e. 2-methyl butane) and option D (n-pentane) has same molecular formula. Hence, they are isomers.

However, compound present in option A, is the same compound provided in question. Hence, it is not an isomer. Compounds reported in option B and C has one carbon atom less and more, respectively as compared to the compound reported in question. Hence, they are also not isomers. 

5 0
3 years ago
Determine the limiting reactant when 30.0 g of propane, C3H8, is burned with 75.0 g of oxygen.
AnnZ [28]

<u>Answer:</u> The limiting reagent is oxygen gas.

<u>Explanation:</u>

Limiting reagent is defined as the reactant that is present in less amount and it limits the formation of products.

Excess reagent is defined as the reactant which is present in large amount.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}      .....(1)

  • <u>For propane:</u>

Given mass of propane = 30.0 g

Molar mass of propane = 44.1 g/mol

Putting values in equation 1, we get:

\text{Moles of propane}=\frac{30.0g}{44.1g/mol}=0.680mol

  • <u>For oxygen:</u>

Given mass of oxygen = 75.0 g

Molar mass of oxygen = 32 g/mol

Putting values in equation 1, we get:

\text{Moles of propane}=\frac{75.0g}{32g/mol}=2.34mol

The chemical equation for the combustion of propane follows:

C_3H_8(g)+5O_2(g)\rightarrow 3CO_2(g)+4H_2O(l)

By Stoichiometry of the reaction:

5 moles of oxygen gas reacts with 1 mole of propane.

So, 2.34 moles of oxygen gas will react with = \frac{1}{5}\times 2.34=0.468mol of propane

As, given amount of propane is more than the required amount. So, it is considered as an excess reagent.

Thus, oxygen is considered as a limiting reagent because it limits the formation of product.

Hence, the limiting reagent is oxygen gas.

3 0
3 years ago
Strong acids are corrosive in nature​
Yuri [45]
Yes. Strong bases are too. In fact, they’re more dangerous to your skin than acids.
8 0
3 years ago
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