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2 years ago

Determine the quantity of bromine atoms in 18.0g of HgBr2 (using factor label method)

1 answer:

8 0

Considering the definition of molar mass and Avogadro's Number, the quantity of bromine atoms in 18.0g of HgBr₂ is 6.023×10²² atoms.

<h3>Definition of molar mass</h3>

The molar mass of substance is a property defined as its mass per unit quantity of substance, in other words, molar mass is the amount of mass that a substance contains in one mole.

The molar mass of a compound (also called Mass or Molecular Weight) is the sum of the molar mass of the elements that form it (whose value is found in the periodic table) multiplied by the number of times they appear in the compound.

<h3>Molar mass of HgBr₂</h3>

In this case, you know the molar mass of the elements is:

Hg= 200 g/mole
Br= 79.9 g/mole

So, the molar mass of the compound HgBr₂ is calculated as:

HgBr₂= 200 g/mole + 2×79.9 g/mole

Solving:

HgBr₂= 359.98 g/mole

Definition of Avogadro's Number

Avogadro's Number or Avogadro's Constant is called the number of particles that make up a substance (usually atoms or molecules) and that can be found in the amount of one mole of said substance. Its value is 6.023×10²³ particles per mole. Avogadro's number applies to any substance.

<h3>Quantity of bromine atoms in 18.0g of HgBr₂</h3>

Factor-label describes a technique to convert one quantity to another quantity. This method uses the fact that any number or expression can be multiplied by one without changing its value; this is, consists in multiply the value you are given, unit of measurement included, by the conversion factor in fraction form.

Finally, knowing that 2 moles of Br are present in 1 mole of HgBr₂, and considering the molar mass of HgBr₂ and the definition on Avogadro's number, the quantity of bromine atoms in 18.0g of HgBr₂ is calculated as:

$18 gr HgBr_{2}\frac{1 mole HgBr_{2}}{359.98 gHgBr_{2}} \frac{2 mole Br}{1 mole HgBr_{2} } \frac{6.023x10^{23}atoms Br }{1 mole Br} =6.023x10^{22}atoms$

In summary, the quantity of bromine atoms in 18.0g of HgBr₂ is 6.023×10²² atoms.

Learn more about

molar mass:

<u>brainly.com/question/5216907</u>

<u>brainly.com/question/11209783</u>

<u>brainly.com/question/7132033</u>

<u>brainly.com/question/17249726</u>

Avogadro's Number:

<u>brainly.com/question/11907018</u>

<u>brainly.com/question/1445383</u>

<u>brainly.com/question/1528951</u>

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1-butanol yields 1-bromobutane in the presence of concentrated sulfuric acid and an excess of sodium bromide. CH3CH2CH2CH2OH (l)

Zanzabum

Answer:

The answer to your question is: yield = 56.27%

Explanation:

Data

CH3CH2CH2CH2OH (l) → CH3 CH2CH2CH2Br

18.54 ml 1-butanol 15.65 g of 1-bromobutane

% yield = ?

density = 0.81 g/ml

MM = 74 g 1- butanol

MM = 137 g 1-bromobutane

Process

Calculate mass of 1- butanol

density = mass/volume

mass = density x volume

mass = 0.81 x 18.54

mass = 15.02 g of 1-butanol

Theoretical yield

74 g of 1- butanol ----------------- 137 g of 1-bromobutane

15.02 g of 1- butanol ------------- x

x = (15.02 x 137) / 74

x = 27.81 g of 1-bromobutane

% yield = experimental yield / theoretical yield x 100

% yield = 15.65 / 27.81 x 100

% yield = 56.28

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4 years ago

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3 years ago

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Alenkasestr [34]

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1 year ago

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The elemental mass percent composition of ascorbic acid (vitamin C ) is 40.92% C , 4.58% H , and 54.50% O . Determine the empiri

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The empirical formula of ascorbic acid is C6H8O6.

<h3>Empirical formula</h3>

To calculate the empirical mass of a compound from the mass percentage of each element, the value of the<u> molar mass </u>of each element is used, which in this case corresponds to:

$MM_C= 12g/mol\\MM_H=1g/mol\\MM_O=16g/mol$

From this, we consider that the compound has 100 grams, so the number of moles of each element will be equal to:

$C = \frac{40.92}{12} = 3.41 \\H = \frac{4.58}{1}=4.58\\ O =\frac{54.50}{16}=3.41$

Now, divide all the values found by the <u>smallest value</u>, to find the amount present in each element:

$C = \frac{3.41}{3.41} = 1\\ H = \frac{4.58}{3.41} = 1.34\\O = \frac{3.41}{3.41} = 1$

As you can see, the value of moles of hydrogen resulted in a decimal number, so it is necessary to multiply all values by a number in common until the three meet as integers:

$C = 1 \times 6 = 6\\H = 1.34 \times 6 = 8\\O = 6 \times 6 = 6$

So, the empirical formula of ascorbic acid is C6H8O6.

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3 years ago

Using complete sentences, explain how to predict the products and balance the reaction between sulfuric acid and potassium hydro

Dahasolnce [82]

The product(s) of the reaction are to be determined given the reactants, sulfuric acid and potassium hydroxide. sulfuric acid is an acid, whereas potassium hydroxide is a basic. The results of this neutralizing process are salt and water.

<h3>What is the reaction between sulfuric acid and potassium hydroxide?</h3>

The result will be, H+ from H₂SO₄ reacts with OH- from KOH to generate H₂O. Also, K+ reacts with SO₄²⁻ to create K₂SO4₄

As a result, the balanced equation will be:

$\rm H_2SO_4 + 2KOH --- > K_2SO_4 + 2H_2O$

Thus, the product(s) of the reaction are to be determined given the reactants, sulfuric acid and potassium hydroxide. Sulfuric acid is an acid, whereas potassium hydroxide is a basic. The results of this neutralizing process are salt and water.

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