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9966 [12]
3 years ago
10

Five oranges were selected at random from a crate of 53 oranges. Their diameters were measured, in millimeters, and then recorde

d.
Diameters: 46, 39, 53, 61, 49



What is the estimated mean diameter of the 53 oranges in the crate?



mm
Mathematics
2 answers:
Serga [27]3 years ago
5 0
Add all of the numbers together and then divide by how many numbers there are. 
(46+39+53+61+49=248)[ 248\5=49.6] 
49.6 is your answer.
sergejj [24]3 years ago
3 0
The average diameter is 49.6mm
Hope I helped!!!
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AleksandrR [38]

Answer:

58,187.5 m²

Step-by-step explanation:

1 cm : 25 m

7 cm = 25 × 7 m

7 × 25 = 175 m

13.3 × 25 = 332.5 m

area = 332.5 m × 175 m

7 0
2 years ago
Michael is a basketball player who regularly shoots sets of 2 free-throws. Suppose that each shot has probability 0.60. , point,
Sati [7]

Answer:

0.1306

Step-by-step explanation:

This is a binomial distribution problem

Binomial distribution function is represented by

P(X = x) = ⁿCₓ pˣ qⁿ⁻ˣ

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x = Number of successes required = 6

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P(X = 6) = ⁷C₆ (0.6)⁶ (0.4)⁷⁻⁶ = 0.1306368 = 0.1306

Hope this Helps!!!

4 0
3 years ago
The perimeter of a rectangle is 40 feet. if the lenght is 15 feet, 6 inches, what is the width
SpyIntel [72]
4 feet 6 inches
Step-by-step explanation:
P=2(l+w) [the addition of all sides of the rectangle]
P = 40'
L = 15’6”
So, 40' = 2 (15’6’ + w)
40' = 31’ + 2w
9' = 2w
4’6” = w
If it's easier you can break it change feet into inches and then change back to feet.
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Answer:

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nirvana33 [79]
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