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2 years ago

Suppose that the cost of renting a snowmobile is $37.50 for 5 hours.

Mathematics

1 answer:

Andreyy892 years ago

3 0

Answer:

A) Cost is the dependent variable

B) $75.00

Step-by-step explanation:

We are given the following information in the question:

Cost of renting a snowmobile for 5 hours = $37.50

If c represents the cost and h represents the hours. then cost is the dependent variable as it depends upon the number of hours for which the snowmobile is rented.

Cost of renting a snowmobile for 1 hour =

$\displaystyle\frac{\text{Cost for 5 hours}}{\text{Number of hours}} = \frac{37.5}{5} = \$7.5$

Cost of renting 2 snowmobiles for 5 hours =

$\text{Cost of renting a snowmobile for 5 hours }\times 2 = 37.5\times 2 = \$75$

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A triangle forms the front of the Pantheon in Rome, Italy. Classify the triangle based on its sides. Then classify it based on i

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(See explanation for further details)

Step-by-step explanation:

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2 years ago

The data show the average monthly temperatures for two cities over a 6-month period. City 1: {20, 24, 40, 63, 76, 89} City 2: {4

Mrac [35]

Answer:

The MAD of city 2 is less than the MAD for city 1, which means the average monthly temperature of city 2 vary less than the average monthly temperatures for City 1.

Step-by-step explanation:

For comparing the mean absolute deviations of both data sets we have to calculate the mean absolute deviation for both data sets first,

So for city 1:

$Mean = x1 = \frac{20+24+40+63+76+89}{6}$

$x1 = \frac{312}{6}$

$x1 = 52$

Now to calculate the mean deviations mean will be subtracted from each data value. (Note: The minus sign is ignored as the deviation is the distance of value from the mean and it cannot be negative. For this purpose absolute is used)

$20-52 = -32=32\\24-52=-28=28\\40-52=-12=12\\63-52=11\\76-52=24\\89-52=37$

The deviations will be added then. $Mean Absolute Deviation = \frac{32+28+12+11+24+37}{6} \\=\frac{144}{6}\\=24$

So the mean absolute deviation for city 1 is 24 ..

For city 2:

$Mean = x2 = \frac{41+50+58+62+72+83}{6}$

$x2 = \frac{366}{6}$

$x2 = 61$

Now to calculate the mean deviations mean will be subtracted from each data value. (Note: The minus sign is ignored)

$41-61=-20=20\\50-61=-11=11\\58-61=-3=3\\62-61=1\\72-61=11\\83-61=22$

The deviations will be added then. $Mean Absolute Deviation = \frac{20+11+3+1+11+22}{6} \\=\frac{68}{6}\\=11.33$

So the MAD for city 2 is 11.33 ..

So,

The MAD of city 2 is less than the MAD for city 1, which means the average monthly temperature of city 2 vary less than the average monthly temperatures for City 1.

3 0

2 years ago

Read 2 more answers