A group of 10 friends ate dinner. They added a 15% tip, and it cost $99.50. What did the meal cost BEFORE the tip?

Mathematics

2 answers:

Cloud [144]3 years ago

8 0

You would do $99.50x.85= 84.575= 84.58$

siniylev [52]3 years ago

4 0

Cost of meal before tip is $86.52

You might be interested in

White raven [17]

The ratio of the volume of pipe a to the volume of pipe b is 27:1 .

<h3>What is cylinder?</h3>

A cylinder is a three-dimensional shape consisting of two parallel circular bases, joined by a curved surface. The center of the circular bases overlaps each other to form a right cylinder.

Given that,

Radius of pipe a is 6 cm, and the radius of pipe b is 2 cm.

We know that the volume of cylinder is :- $\pi r^{2}h$

where r is radius and h is height of the cylinder.

If two figures are similar then ratio of volume is equal to the cube of any dimension.

The ratio of the volume of Pipe a to the volume of Pipe b :-

$\frac{V(a)}{V(b)}=\frac{6^{3} }{2^{3} }$

= $\frac{27}{1}$

Hence, The ratio of the volume of pipe a to the volume of pipe b is 27:1 .

To learn more about cylinder from the given link:

brainly.com/question/1392572

#SPJ4

7 0

1 year ago

What is the area of the logo?

Ludmilka [50]

Answer:

$the \: area \: of \: the \: logo \: is \: {91cm}^{2}$

Step-by-step explanation:

To determine the area of the logo you have to calculate the area of the triangle and the square that comform it and then add the four areas.

Area of the square.

To calculate the area of the square you have to calculate the square of one of its sides, following the formula:

$a = {a}^{2}$

Where "a" is the length of one of its side.

The side length of the square is a=7cm, so its area will be:

$asquare = {7}^{2} \\ asquare = {49cm}^{2}$

Area of the triangles.

The three triangles are equal, they have a base equal to the side of the square, i.e. with a length of 7cm, and their height is h=4cm.

To calculate the area of one triangle, you have to multiply its base by its height and divide by 2, following the formula:

$a = \frac{b.h}{2} \\ a = \frac{7.4}{2} \\ a = \frac{28}{2} \\ a = {14cm}^{2}$

The area calculated the correspond to one triangle, since all triangles are congruent, you have to multiply the said area by 3 to determine the area of three figures:

$atriangles = 3a \\ atriangles = {42cm}^{2}$