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vredina [299]
3 years ago
8

Dave krug finances a new automobile by paying $6,500 cash and agreeing to make 40 monthly payments of $500 each, the first payme

nt to be made one month after the purchase. the loan bears interest at an annual rate of 12%. what is the cost of the automobile?
Mathematics
1 answer:
Troyanec [42]3 years ago
6 0
P = (C - down payment)*D

D = [i/12]/[1-(1+i/12)^-12n] = [0.12/12]/[1-(1+0.12/12)^-40] = 0.03046

Therefore,

500 = (C-6,500)*0.03046
C-6,500 = 500/0.03046 = 16,417.34
C = 22,917.34

The cost of the automobile was $22,917.34
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Ber [7]
3.6 is the answer youre looking for
8 0
3 years ago
To increase the value of estimated Cohen's d, a researcher increases the sample size. Will this change the value of d?
tatyana61 [14]

Answer:

a. A) Yes; as sample size increases, effect size increases.

b. A) The critical value increases.

Step-by-step explanation:

a.

If all possible samples of size N are drawn from a finite population, Np, without replacement, and the standard deviation of the mean values of the sampling distribution of means is determined then:

σx =d  √N

d = σx . √N

d ∞ N

from this, we can say d is directly proportional to √N

where σx is the standard deviation of the sampling distribution of  means and d is the standard deviation of the population’. The standard deviation of a sampling distribution of mean values is called the standard error of the means,

therefore, we can conclude that:

A) Yes; as sample size increases, effect size increases.

b.

In this estimate, tc is called the confidence coefficient for small samples,  d is the standard deviation of the sample, x is the mean value of the sample and N is the number of members in the sample.

When determining the t-value, given by

t =( (x−µ) /s) * \sqrt{N-1}

it is necessary to know the sample parameters x and s and the population parameter µ. x and s can be calculated for the sample, but usually an estimate has to be made of the population mean µ, based on the sample mean value.

from the above equation it can be deduced that t value is determined with the sample size, and as the sample size increases

A) The critical value increases.

3 0
3 years ago
Assume that the wavelengths of photosynthetically active radiations (PAR) are uniformly distributed at integer nanometers in the
Lana71 [14]
There are 26 integers in the set \{630,631,\ldots,655\}. If the wavelength of light is uniformly distributed, then the probability that it has a wavelength of any one of these integers is \dfrac1{26}, so the distribution of wavelengths has probability mass function

\mathbb P(X=x)=\begin{cases}\dfrac1{26}&\text{for }630\le x\le655,x\in\mathbb Z\\\\0&\text{otherwise}\end{cases}

The mean (expected value) is given by

\mathbb E(X)=\displaystyle\sum_xx\mathbb P(X=x)

and the variance by

\mathbb V(X)=\mathbb E(X^2)-\mathbb E(X)^2

First, the mean:

\mathbb E(X)=\displaystyle\sum_{x=630}^{655}x\mathbb P(X=x)=\frac1{26}\sum_{x=630}^{655}x
\mathbb E(X)=\dfrac{16705}{26}\approx643

(rounded up from an exact value of 642.5)

Now for the variance:

\mathbb E(X^2)=\displaystyle\sum_xx^2\mathbb P(X=x)=\frac1{26}\sum_{x=630}^{655}x^2
\mathbb E(X^2)=412862.5

Meanwhile, \mathbb E(X)^2=642.5^2=412806, which gives a total variance of

\mathbb V(X)=412862.5-412806\approx57

(rounded up from 56.5)
3 0
3 years ago
Let two events A and B be independent. Knowing P(A)=0.8 and P(A+B)=0.93. Calculate the probability P(B).
Tems11 [23]

Answer:

Hello,

<u>P(B)=0.65</u>

Step-by-step explanation:

If P(A+B) means P(A∪B)=0.93 then you may read below.

Let's say x=P(B)

A and B being independent, P(A∩B)=P(A)*P(B)=0.8*x

Since P(A∪B)=P(A)+P(x)-P(A∩B) ,

0.93=0.8+x-0.8*x

0.2*x=0.13

x=0.65

3 0
3 years ago
PLS ANSWER MY QUESTION WITH AN EXPLANATION NOT JUST AN ANSWER
masha68 [24]

Step-by-step explanation:

Perimeter is the sum of all the outside edges, so for a rectangle the perimeter (P) is (length + length + width + width).

P = length + length + width + width

P = 2x + 6 + 2x + 6 + x + x

P = 6x + 6

So the perimeter of the rectangle is 6x+6

3 0
3 years ago
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