Given:
The graph of a quadratic function passes through the points (5,31) (3,11) (0,11).
To find:
The equation of the quadratic function.
Solution:
A quadratic function is defined as:
...(i)
It is passes through the point (0,11). So, substitute in (i).
Putting in (i), we get
...(ii)
The quadratic function passes through the point (5,31). So, substitute in (ii).
Divide both sides by 5.
...(iii)
The quadratic function passes through the point (3,11). So, substitute in (ii).
Divide both sides by 3.
...(iv)
Subtracting (iv) from (iii), we get
Putting in (iv), we get
Putting in (ii), we get
Therefore, the required quadratic equation is .
Answer:
$614.2
Step-by-step explanation:
Um I just calculated it. I'm in Algebra 2 so it's light work
To answer this, you should "subtract" x+y=7 from 3x+y=45.
What is left is 2x=38, where x then equals 19.
Plug this value into any of the equations (I will choose x+y=7 for simplicity).
19+y=7, y=-12
Check this answer by plugging it into the other equation.
3(19) + (-12) =45
45=45 so it is correct
X=19 and Y=-12
Answer:
b is the answer because an acute traingle is angles that are below 90 degrees and scale trainle because none of the side equal to each other but it equals a total of 180 degrees.
Hey!
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Solution in picture!
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Answer: (-8, 10)
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Hope This Helped! Good Luck!