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3 years ago

7 log(15/16)+6log(8/3)+5log(2/3)+log(32/25)by logarithm laws

Mathematics

1 answer:

hammer [34]3 years ago

4 0

Answer:

1.5871

Step-by-step explanation:

According to the Question,

we have, 7 log(15/16)+6log(8/3)+5log(2/3)+log(32/25)

The Solution, With Basic Properties of Log.

7*log15-7*log16+6*log8-6*log3+5*log2-5*log3+log32-log25

7*1.176-7*1.204+6*0.903-6*0.477+5*0.3010-5*0.477+1.505-1.3979

on Solving, We get

1.5871

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Butoxors [25]

Answer:

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Step-by-step explanation:

Previous concepts

A chi-square goodness of fit test "determines if a sample data matches a population".

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$\sum_{i=1}^n \frac{(O_i -E_i)^2}{E_i}$

And if we replace we got:

$\chi^2 = \frac{(30-25)^2}{25} +\frac{(20-25)^2}{25} =1 +1 =2$

Part 2

For this case the degreed of freedom are given by:

$df = c-1 = 2-1$

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And we can calculate the p value given by:

$p_v = P(\chi^2_{1} >2)=0.157$

And we can find the p value using the following excel code:

"=1-CHISQ.DIST(2,1,TRUE)"

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3 years ago

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enyata [817]

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3 years ago

7 log(15/16)+6log(8/3)+5log(2/3)+log(32/25)by logarithm laws​

7 log(15/16)+6log(8/3)+5log(2/3)+log(32/25)by logarithm laws