Answer:
y-1= -4(x-(-3))
y minus 1 = negative 4 left-bracket x minus (negative 3) right-bracket
Step-by-step explanation:
The formula for point slope form is written:
. Now we fill in our know information. m=-4 (because that is the slope),
=1 (It is the y value in the ordered pair),
= -3 (It is the x value in the ordered pair).
y-1=-4(x- (-3))
Answer:
Total area = 237.09 cm²
Step-by-step explanation:
Given question is incomplete; here is the complete question.
Field book of an agricultural land is given in the figure. It is divided into 4 plots. Plot I is a right triangle, plot II is an equilateral triangle, plot III is a rectangle and plot IV is a trapezium, Find the area of each plot and the total area of the field. ( use √3 =1.73)
From the figure attached,
Area of the right triangle I = 
Area of ΔADC = 
= 
= 
= 
= 
= 30 cm²
Area of equilateral triangle II = 
Area of equilateral triangle II = 
= 
= 73.0925
≈ 73.09 cm²
Area of rectangle III = Length × width
= CF × CD
= 7 × 5
= 35 cm²
Area of trapezium EFGH = 
Since, GH = GJ + JK + KH
17 = 
12 = 
144 = (81 - x²) + (225 - x²) + 2
144 - 306 = -2x² + 
-81 = -x² + 
(x² - 81)² = (81 - x²)(225 - x²)
x⁴ + 6561 - 162x² = 18225 - 306x² + x⁴
144x² - 11664 = 0
x² = 81
x = 9 cm
Now area of plot IV = 
= 99 cm²
Total Area of the land = 30 + 73.09 + 35 + 99
= 237.09 cm²
Answer:
2304
Step-by-step explanation:
<u>Given :- </u>
- A geometric sequence is given to us which is 9 , -18 , 36.
And we need to find out the 9th term of the sequence. Here firstly we should find the Common Ratio and then we can substitute the respective values in the formula to find the nth term of a geometric sequence .
<u>Common Ratio :- </u>
CR = -18÷ 9 = -2
<u>The </u><u>9</u><u> th term :- </u>
T_n = arⁿ - ¹
T_9 = 9× (-2) ⁹ - ¹
T_9 = 9 × (-2)⁸
T_9 = 9 × 256
T_9 = 2304
<u>Hence the 10th term is </u><u>2</u><u>3</u><u>0</u><u>4</u><u>.</u>