Answer:
t = 0.293 s and 14.52 s
Step-by-step explanation:
The heights of the ball in feet is given by the equation as follows :
Where t is the number of seconds after the ball was thrown.
We need to find is the ball 18 ft above the moon's surface.
Put S = 18 ft
It is a quadratic equation. Its solution is given by :
So, the ball is at first 0.293 s and then 14.52 s above the Moon's surface.
(y -3)^2 = 4y - 12
Expand.
(y-3)(y -3) = 4y - 12
y² - 6y + 9 = 4y - 12
y² - 6y -4y + 9 + 12 = 0
y² - 10y + 21 = 0
Factors are -7y and - 3y
y² - 10y + 21 = 0
y² - 3y - 7y + 21 = 0
y(y - 3) -7(y - 3) = 0
(y - 3)(y - 7) = 0
y-3 = 0 or y - 7 = 0
y = 0 + 3 or y = 0 + 7
y = 3 or 7
First you have to convert the denominators to the Lowest Common Multiple (unless the denominators are equal, of course).
Example 1/4 + 1/2
The LCM of 2 and 4 = 4 so we can write 1/2 as 1*2/2*2 = 2/4.
Now we can add:-
1/4 + 2/4 = 3/4.
Same thing goes for subtraction.
Example 2:-
5/6 - 1/7 :-
LCM of 6 and 7 = 6*7 = 42 so we have:-
5*7 / 6*7 - 1*6 / 7*6
= 35/42 - 6/42 = 29/42
Answer:
Step-by-step explanation:
s = n(a + 1)
n(a + 1) = s
a + 1 = s/n
a = s/n - 1
Answer:
y = x-2
Step-by-step explanation:
y = mx + b as an equation
m = slope
slope = (change in y) / (change in x) = (y₂-y₁)/(x₂-x₁) = (y₁-y₂)/(x₁-x₂) = (2-(-2))/(4-0) = 4/4 = 1
y = 1*x + b
plug a value in, e.g. (0, -2)
-2 = 1 * 0 + b
-2 = b
our equation is thus
y = x - 2
