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marin [14]
3 years ago
5

Based on information from the periodic table, what does this image represent? HE 4 Protons e 5 Neutrons = 2 Electrons A. A negat

ively charged beryllium ion
B. A neutral boron atom
C. A neutral beryllium atom
D. A positively charged beryllium ion​

Mathematics
1 answer:
shutvik [7]3 years ago
6 0

Answer:

D. A positively charged beryllium ion

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What is 4/8 + 2/8 = ?
Deffense [45]

Answer:

4/8 =1/2

2/8 = 1/4

1/2+1/4, we take Lcm,

2+4/2 =6/4

3/2

7 0
3 years ago
Read 2 more answers
The point (1/3,1/4) lies on the terminal said of an angle. Find the exact value of the six trig functions and explain which func
katrin2010 [14]

Answer:

sine and cosec are inverse of each other.

cosine and sec are inverse of each other.

tan and cot are inverse of each other.

Step-by-step explanation:

Given point on terminal side of an angle (\frac{1}{3},\frac{1}4).

Kindly refer to the attached image for the diagram of the given point.

Let it be point A(\frac{1}{3},\frac{1}4)

Let O be the origin i.e. (0,0)

Point B will be (\frac{1}{3},0)

Now, let us consider the right angled triangle \triangle OBA:

Sides:

Base, OB = \frac{1}{3}\\Perpendicular, AB = \frac{1}{4}

Using Pythagorean theorem:

\text{Hypotenuse}^{2} = \text{Base}^{2} + \text{Perpendicular}^{2}\\\Rightarrow OA^{2} = OB^{2} + AB^{2}\\\Rightarrow OA^{2} = \frac{1}{3}^{2} + \frac{1}{4}^{2}\\\Rightarrow OA = \sqrt{\frac{1}{3}^{2} + \frac{1}{4}^{2}}\\\Rightarrow OA = \sqrt{\frac{4^2+3^2}{3^{2}.4^2 }}\\\Rightarrow OA = \frac{5}{12}

sin \angle AOB = \dfrac{Perpendicular}{Hypotenuse}

\Rightarrow sin \angle AOB = \dfrac{\frac{1}{4}}{\frac{5}{12}}\\\Rightarrow sin \angle AOB = \dfrac{3}{5}

cos\angle AOB = \dfrac{Base}{Hypotenuse}

\Rightarrow cos \angle AOB = \dfrac{\frac{1}{3}}{\frac{5}{12}}\\\Rightarrow cos\angle AOB = \dfrac{4}{5}

tan\angle AOB = \dfrac{Perpendicular}{Base}

\Rightarrow tan\angle AOB = \dfrac{3}{4}

cosec \angle AOB = \dfrac{Hypotenuse}{Perpendicular}

\Rightarrow cosec\angle AOB = \dfrac{5}{3}

sec\angle AOB = \dfrac{Hypotenuse}{Base}

\Rightarrow sec\angle AOB = \dfrac{5}{4}

cot\angle AOB = \dfrac{Base}{Perpendicular}

\Rightarrow cot\angle AOB = \dfrac{4}{3}

3 0
3 years ago
9 pencils cost $7.74<br> Which equation would help determine the cost of 6 pencils?
Stells [14]

Answer $5.16

Step-by-step explanation:

$7.74 divided by 9 is 0.86 so 0.86 per pencil mutiply that by 6 because you have six pencils and you get 5.16 for six pencils

5 0
3 years ago
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Kevin is a quarterback on the football team.he completed 36 passes during the season.his second-string replacement,Mark complete
anastassius [24]
36 × \frac{2}{9}

Since 9 is a factor of 36 you can reduce the 36 to 4 and the 9 to one 

Then just multiply what is left

4 <span>× 2 = 8

So, Mark completed 8 passes.</span>
3 0
3 years ago
If Shape 1 is a scale copy of shape 2, What side corresponds of side AB?
igor_vitrenko [27]

Answer:

the answer is D. WX

Step-by-step explanation:

just look at the figure

6 0
3 years ago
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