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Lelechka [254]
2 years ago
14

Find the Slope of Y=X-2

Mathematics
2 answers:
DIA [1.3K]2 years ago
7 0

<em>Answer:</em>

Slope= 2.000/2.000= 1.000

<em>Have a beautiful day and stay safe.</em>

<em></em>

Marina86 [1]2 years ago
3 0

Answer:

The slope is 1

Step-by-step explanation:

hope this helps

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Solve for f: 6f + 9g = 3g + f
lozanna [386]
Hi there!

Let's solve this equation step by step!
6f + 9g = 3g + f

To solve for f, we need to bring all the terms in the equation with an f in it to the left, and all the other terms (with a g) to the right.

First subtract f from both sides.
5f + 9g = 3g

Now subtract 9g from both sides.
5f = -6g

And finally divide both sides by 5.
f = (-6/5)g

Hence, your answer;
f =  -  \frac{6}{5} g

~ Hope this helps you!
6 0
3 years ago
Read 2 more answers
2
Zigmanuir [339]

Answer:

The weight of the water in the pool is approximately 60,000 lb·f

Step-by-step explanation:

The details of the swimming pool are;

The dimensions of the rectangular cross-section of the swimming pool = 10 feet × 20 feet

The depth of the pool = 5 feet

The density of the water  in the pool = 60 pounds per cubic foot

From the question, we have;

The weight of the water in Pound force = W = The volume of water in the pool given in ft.³ × The density of water in the pool given in lb/ft.³ × Acceleration due to gravity, g

The volume of water in the pool = Cross-sectional area × Depth

∴ The volume of water in the pool = 10 ft. × 20 ft. × 5 ft. = 1,000 ft.³

Acceleration due to gravity, g ≈ 32.09 ft./s²

∴ W = 1,000 ft.³ × 60 lb/ft.³ × 32.09 ft./s² = 266,196.089 N

266,196.089 N ≈ 60,000 lb·f

The weight of the water in the pool ≈ 60,000 lb·f

6 0
2 years ago
Need help ASAP! ——————————————————————————————
Taya2010 [7]

Answer:wanted to help but not that smart

Step-by-step explanation:

4 0
2 years ago
Cam someone help me out please
Sergio039 [100]

Answer:428.67

Step-by-step explanation:

πr (r+square root(h2+r2) plug in the numbers

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3 years ago
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Please repost... picture is all black
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