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Molodets [167]
3 years ago
8

Ellie’s new kitten is 412 inches long. Her rabbit is 325 inches longer than her kitten. Which equation can be used to find the l

ength of Ellie’s rabbit, r? A.412−325=r
B.325+412=r C.412−r=325 D.325+r=412
Mathematics
1 answer:
vodka [1.7K]3 years ago
6 0

Answer:

Step-by-step explanation:

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The length of DE (the minor arc) is 52 cm. What is the circumference of OF?
nordsb [41]

Answer:

D, 312 CM.

Step-by-step explanation:

DE/C = 60/360 = 1/6

Cross-multiplying

C = 6DE = 6 x 52 = 312 CM

8 0
3 years ago
How to draw a model of 3/10
-BARSIC- [3]
Draw a pizza with 10 slices and shade 3 slices
4 0
3 years ago
A film lasts 2 hours and 35 minutes. Greg is going out at 8.15 . If he starts watching the film at 5.30 will he have time to war
Dmitry [639]

Answer:

Yes, he will have enough time to watch the entire film.

Step-by-step explanation:

5:30 to 6:30 is 1 hour of the movie completed.

6:30 to 7:30 is 2 hours completed.

7:30 plus 30 minutes brings him to 8:00.

8:00 plus the additional 5 minutes brings Greg to 8:05.

His movie ends at 8:05, so he will be able to watch the entire movie before going out.

8 0
3 years ago
Read 2 more answers
Does the frequency distribution appear to have a normal distribution using a strict interpretation of the relevant​ criteria?Tem
Xelga [282]

Answer:

B. No, this distribution does not appear to be normal

Step-by-step explanation:

Hello!

To observe what shape the data takes, it is best to make a graph. For me, the best type of graph is a histogram.

The first step to take is to calculate the classmark`for each of the given temperature intervals. Each class mark will be the midpoint of each bar.

As you can see in the graphic (2nd attachment) there are no values of frequency for the interval [40-44] and the rest of the data show asymmetry skewed to the left. Just because one of the intervals doesn't have an observed frequency is enough to say that these values do not meet the requirements to have a normal distribution.

The answer is B.

I hope it helps!

3 0
3 years ago
Please solve this question!!​
GaryK [48]

Answer:  (i) 1/221     (ii) 11/221      (iii) 95/663        (iv) 1/663

<u>Step-by-step explanation:</u>

(i) A deck of cards contains 4 Kings out of 52 total cards

1st draw: 4 Kings out of 52 total cards → 4/52 = 1/13

2nd draw: 3 remaining Kings out of 51 total remaining cards  →  3/51 = 1/17

  <u>1st Draw </u>                   <u>2nd Draw </u>                  <u>Outcome</u>         <u>Probability</u>

 King: P(K) = 1/13        King: P(K₂/K₁) = 1/17     King, King       (1/13) x (1/17) = 1/221

*************************************************************************************************

(ii) A deck of cards contains 4 Jacks, 4 Queens, & 4 Kings out of 52 total cards

1st draw: 12 Face cards out of 52 total cards → 12/52 = 3/13

2nd draw: 11 remaining Face cards out of 51 total remaining cards  →  11/51

<u>1st Draw </u>                 <u>2nd Draw </u>                  <u>Outcome</u>       <u>Probability</u>

 Face: P(F) = 3/13    Face: P(F₂/F₁) = 11/51   Face,Face     (3/13) x (11/51) = 11/221

*************************************************************************************************

(iiI) A deck of cards contains 26 black cards out of 52 total cards but there are 2 black Jacks, 2 black Queens, and 2 black Kings.

1st draw: 20 Black (not Face) cards out of 52 total cards → 20/52 = 5/13

2nd draw: 19 remaining Black (not Face) cards out of 51 total remaining cards  →  19/51

  <u>1st Draw </u>                 <u>2nd Draw </u>                       <u>Outcome</u>   <u>Probability</u>

Black: P(B~) = 5/13   Black: P(B~₂/B~₁) = 19/51    B~,B~    (5/13) x (19/51) = 95/663

*************************************************************************************************

(ii) A deck of cards contains 4 Aces out of 52 total cards

1st draw: 4 Aces out of 52 total cards → 4/52 = 1/13

2nd draw: 1 Queen of Hearts out of 51 total remaining cards  →  1/51

  <u>1st Draw </u>                 <u>2nd Draw </u>                   <u>Outcome</u>         <u>Probability</u>

 Ace: P(A) = 1/13      Qh: P(Qh₂/A₁) = 1/51   Ace,Queen(h)   (1/13) x (1/51) = 1/663

7 0
4 years ago
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