Consider the equation

A beach toy in the shape of a pyramid has a rectangular base with dimensions of 4 inches by 12 inches. The height of the rectang

Alexxandr [17]

Answer:

80in3

Step-by-step explanation:

12 x 4 = 48

48 / 2 = 24

24 x 10 =240

240 / 3 = 80

So your answer is 80in3

7 0

2 years ago

Mr. Good Wrench advertises that a customer will have to wait no more than 30 minutes for an oil change. A sample of 26 oil chang

Andru [333]

Answer:

The 90% confidence interval for the population standard deviation waiting time for an oil change is (3.9, 6.3).

Step-by-step explanation:

The (1 - α)% confidence interval for the population standard deviation is:

$CI=\sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{\alpha/2, (n-1)}}}\leq \sigma\leq \sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{1-\alpha/2, (n-1)}}}$

The information provided is:

n = 26

s = 4.8 minutes

Confidence level = 90%

Compute the critical values of Chi-square as follows:

$\chi^{2}_{\alpha/2, (n-1)}=\chi^{2}_{0.10/2, (26-1)}=\chi^{2}_{0.05, 25}=37.652$

$\chi^{2}_{1-\alpha/2, (n-1)}=\chi^{2}_{1-0.10/2, (26-1)}=\chi^{2}_{0.95, 25}=14.611$

*Use a Chi-square table.

Compute the 90% confidence interval for the population standard deviation waiting time for an oil change as follows:

$CI=\sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{\alpha/2, (n-1)}}}\leq \sigma\leq \sqrt{\frac{(n-1)s^{2}}{\chi^{2}_{1-\alpha/2, (n-1)}}}$

$=\sqrt{\frac{(26-1)\times 4.8^{2}}{37.652}}\leq \sigma\leq \sqrt{\frac{(26-1)\times 4.8^{2}}{14.611}}\\\\=3.9113\leq \sigma\leq 6.2787\\\\\approx 3.9 \leq \sigma\leq6.3$

Thus, the 90% confidence interval for the population standard deviation waiting time for an oil change is (3.9, 6.3).

3 0

3 years ago

Which of these layers of earth’s atmosphere is closet to its surface?

wel

Answer:

Troposphere

Step-by-step explanation

contains the air we breath and is often reffered to as the lower atmosphere

3 0

3 years ago

Suppose that time spent on hold per call with customer service at a large telecom company is normally distributed with a mean µ

lana66690 [7]

Answer:

0.3108 is the probability that the sample mean is between 7.8 and 8.2 minutes.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 8 minutes

Standard Deviation, σ = 2.5 minutes

Sample size, n = 25

We are given that the distribution of time spent is a bell shaped distribution that is a normal distribution.

Formula:

$z_{score} = \displaystyle\frac{x-\mu}{\sigma}$

Standard error due to sampling =

$=\dfrac{\sigma}{\sqrt{n}} = \dfrac{2.5}{\sqrt{25}} = 0.5$

P(sample mean is between 7.8 and 8.2 minutes)

$P(7.8 \leq x \leq 8.2)\\\\ = P(\displaystyle\frac{7.8 - 8}{0.5} \leq z \leq \displaystyle\frac{8.2-8}{0.5})\\\\ = P(-0.4 \leq z \leq 0.4})\\\\= P(z < 0.4) - P(z < -0.4)\\\\= 0.6554 -0.3446= 0.3108$

0.3108 is the probability that the sample mean is between 7.8 and 8.2 minutes.

4 0

4 years ago

Please help me on homework. I need help on questions A, E, H, and I...

alisha [4.7K]

Answer:a, 2^3, e, 2^6 h, 2^4

Step-by-step explanation:

2x2x2=8 and 2+2+2+2=8

5 0

3 years ago

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