1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lunna [17]
3 years ago
6

Factorise fully 8 + 49

Mathematics
2 answers:
Talja [164]3 years ago
7 0

Answer:

57

Step-by-step explanation:

<u> </u> <u>8</u>

<u>+ 49</u>

57

Anestetic [448]3 years ago
4 0

Answer: 8 + 49 factored is 57

I hope this helps you

You might be interested in
What is the value of the expression when n=3 6(n^2+2)/n<br><br> 16<br> 22<br> 30<br> 66
Kipish [7]
The correct answer is:  [B]:  " 22 " . 
_________________________________________________________
Explanation:
_________________________________________________________
Given:
_________________________________________________________

\frac{6(n^2 + 2)}{3} ;

Solve when:  "n = 3" ; 

Rewrite the expression; substituting "3" for all values of "n" ; as follows:

  →  \frac{6(3^2+2)}{3} ; 

The "6" cancels out to "2" ; & the "3" cancels out to "1" ; 

→  {since:  " {6 ÷ 3 = 2}" ; and since:  " {2 ÷ 2 = 1}" .
_________________________________________________________
→  Since the "denominator" is "1" ; and any value, divided by "1";  results in that original value;  we can eliminate the denominator.

→  Now, we can rewrite the expression as:
_________________________________________________________
     →  "  2(3² + 2)"  ; 

            =  2(9 + 2) ; 

            =  2(11) ;

            =  " 22 " . 
_________________________________________________________
  →  The answer is:  " 22 " ;   which is:  Answer choice:  [B]:  " 22 " . 
_________________________________________________________
4 0
3 years ago
When writing a geometric proof, which angle relationship could be used alone to justify that two angles are congruent?
Allisa [31]
Vertical angles i believe is the right answer to this problem
5 0
3 years ago
Read 2 more answers
Helpppp pleaseeee ????
Agata [3.3K]

Answer:

LQ = 54

Median = 69

UQ = 94

Step-by-step explanation:

This list is already sorted for you, so you don't need to worry about that, otherwise you would need to sort the numbers in ascending order. To find the median, we do \frac{n+1}{2}, where n is the amount of numbers. This gives us 4, so the median is at position 4, so the median is 69. The lower quartile is simply \frac{n+1}{4}, so 2, so the lower quartile is 54. The upper quartile is \frac{n+1}{2} X 3, so 6, so the upper quartile is 94.

3 0
2 years ago
Quarter past 11 Go Math? Lesson 7.10
fredd [130]

Answer:

11:25

Step-by-step explanation:

A quarter equals 25cents past 11.

11:25

6 0
2 years ago
Need help with this plzzzz
sweet [91]
I would say D my dear friend from what i see from the patterns hope it helps :) and sorry if its wrong i tried lol
8 0
3 years ago
Read 2 more answers
Other questions:
  • The length of a river is 480 km. What is its length on a map with a scale 1:5,000,000?
    14·2 answers
  • The sides of a triangle are in the ratio 3 : 4 : 5. What is the length of each side if the perimeter of the triangle is 90 cm
    5·1 answer
  • There are 2/8 cups of peanuts and 1/4 cup of walnuts. Is there a greater amount of peanuts or walnuts? Explain
    11·1 answer
  • How do you find the root of equation x+8=0
    8·2 answers
  • The ratio of length :width :height of a box is 6 : 3 : 2. What is the volume if the height is 5 centimetres.
    11·2 answers
  • Help due soon plss!!!!
    11·1 answer
  • Area of a circle of radius is 6.5?​
    14·2 answers
  • Classify the following triangle. Check all that apply. 60° 8.4 4.2 30" 7.3 A. Acute B. Equilateral C. Obtuse D. Scalene E. Isosc
    13·1 answer
  • Solve (x + 4)2 – 3(x + 4) – 3 = 0 using substitution. u = x + 4 Select the solution(s) of the original equation.
    6·1 answer
  • Which of the following points lies on the line?
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!