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Aneli [31]
2 years ago
15

Which ratio is equal to 27 : 81?

Mathematics
2 answers:
Assoli18 [71]2 years ago
4 0

Answer:

C) 3: 9

Step-by-step explanation:

27: 81

Ratios are same as fractions, that is why 27:81 = 27 / 81

Now that we go this fraction, let's make it an equivalent fraction:

(27 / 9) / (81/9)

=> 3/9

=> 3 : 9

If my answer helped, kindly mark me as the brainliest!  

Thanks!!

mestny [16]2 years ago
3 0
The answer is C. 3 : 9 :) hope this helped
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Identify the diameter of the circle. Then find the circumference. Round to two decimal places. (C = 2*pi*r)
sleet_krkn [62]

Answer:

diameter=22

circumference=22pi

Step-by-step explanation:

diameter=2*radius

so 2*11=22

circumference=2pi*r

=2*11*pi

=22pi

4 0
3 years ago
In ΔBCD, the measure of ∠D=90°, the measure of ∠C=83°, and DB= 1.3feet. What is the length of CD to the nearest tenth of a foot.
Lina20 [59]

Answer:

CD\approx0.2

Step-by-step explanation:

By the tangent ratio, tanC=\frac{DB}{CD}. Substituting the given values into this equation gives us:

tan83° = \frac{1.3}{CD}

CD*tan83° =1.3 (Multiply both sides of the equation by CD)

CD=\frac{1.3}{tan83\textdegree} (Divide both sides of the equation by tan83\textdegree)

CD=0.15962\approx0.2

Hope this helps!

3 0
2 years ago
Who knows the answer to this ?
Iteru [2.4K]

Answer:

D

Step-by-step explanation:

6 0
2 years ago
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yanalaym [24]

Hope this helped :3

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3 years ago
The Hudson Bay tides vary between 3 feet and 9 feet. The tide is at its lowest point when time (t) is 0 and completes a full cyc
BaLLatris [955]

Answer:

y(t)= 6-3cos(\dfrac{2\pi}{14}t )

Step-by-step explanation:

The function that could model this periodic phenomenon will be of the form

y(t) = y_0+Acos(wt)

The tide varies between 3ft and 9ft, which means its amplitude A is

A =\dfrac{(9-3)ft}{2} \\\\\boxed{A = 3ft}

and its midline y_0 is

y_o=3+3 \\\\\boxed{y_o= 6ft}.

Furthermore, since at t=0 the tide is at its lowest ( 3 feet ), we know that the trigonometric function we must use is -cos(\omega t).

The period of the full cycle is 14 hours, which means

\omega t =2\pi

\omega (t+14)= 4\pi

giving us

\boxed{\omega = \dfrac{2\pi}{14}.}

With all of the values of the variables in place, the function modeling the situation now becomes

\boxed{y(t)= 6-3cos(\dfrac{2\pi}{14}t ).}

8 0
3 years ago
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