All categories

3 years ago

Someone please help

Mathematics

1 answer:

OLEGan [10]3 years ago

4 0

Answer:

e= -2

Step-by-step explanation:

1) distribute so you get 6+0.75e=2-1.25e

2) move the variable to one side so you get 6+2e=2

3) subtract the 6: 2e=-4

4) divide by 2: e= -2

You might be interested in

3/4 x 8 = ? I need help for this question.

ahrayia [7]

Answer:

6 hope this was fast

7 0

2 years ago

Read 2 more answers

After 1 year, $800 deposited in a savings account with simple interest had earned $64 in

stepan [7]

Answer:

Step-by-step explanation:

We will use the equation provided to solve this problem.

$I=Prt$

Lets plug in the values:

$64=800x(1)$ First, divide both sides by 800.

$.08=x(1)$ Multiply x by 1

$x = .08$

Now, we multiply .08 by 100 to get our interest rate:

(.08)100 = 8

The interest rate is 8%

7 0

3 years ago

Find the number of rectangles in 8×8 chessboard. (not just the 1x1 squares)

Gekata [30.6K]

Answer:

288

Step-by-step explanation:

Number of rectangles

____________________________________________________________

1 × 1 squares 9-1 = 1 = 8*8 = 64

1 × 2 squares 9-2 = 7 = 8*7 = 56

1 × 3 squares 9-3 = 6 = 8*6 = 48

1 × 4 squares 9-4 = 5 = 8*5 = 40

1 × 5 squares 9-5 = 4 = 8*4 =32

1 × 6 squares 9-6 = 3 = 8*3 = 24

1 × 7 squares 9-7 = 2 = 8*2 = 16

1 × 8 squares 9-8 = 1 = 8*1 = 8

64 + 56 + 48 + 40 + 32 + 24 + 16 + 8 = 288

Thus,

the number of squares on a chessboard is 228.

Hope this helps :)

8 0

3 years ago

1.) What is the equation of the path of firework #1? Write your equation in general form.

valina [46]

1. I'm assumig that the paths are perfect parabolas

this means that their general forms can be written in $y=ax^2+bx+c$

it's easier to find vertex form first then expand to get general form

vertex form is $y=a(x-h)^2+k$ where the vertex is (h,k) and a is a constant

firework #1

vertex is (10,50), so (h,k)=(10,50) and h=10, k=50

$h_1=a(t-10)^2+50$

to find the value of $a$ , subsitute another point

(0,0)

$0=a(0-10)^2+50)$

$0=100a+50$

$a=\frac{-1}{2}$

so the equation in vertex form is $h_1=\frac{-1}{2}(t-10)^2+50$

expand to get general form

$h_1=\frac{-1}{2}(t^2-20t+100)+50$

$h_1=\frac{-1}{2}t^2+10t-50+50$

$h_1=\frac{-1}{2}t^2+10t$

same as last time

vertex is (10,72) so (h,k)=(10,72) so h=10 and k=72

equation is $h_2=a(t-10)^2+72$

find $a$

use another point

(0,22)

$22=a(0-10)^2+72$

$22=100a+72$

$-50=100a$

$a=\frac{-1}{2}$

so the equation in vertex form is $h_2=\frac{-1}{2}(t-10)^2+72$

range is the numbers that h is allowed to be

think about what h represents. it represents the height of the rocket

from the graph, we can see that the lowest possible height is 0yd and the highest height is 50yd

so range is 0 to 50 or 0≤h≤50

domain is the numbers that t is allowed to be

think about what t represents. it represents how long the rocket has been flying

it will stop flying when it hits the ground or at t=20

it starts flying at t=0

so domain is from 0 to 20 or 0≤t≤20

3 0

3 years ago

Victor opened a savings account that earns 4.5% simple interest. He deposited $5, 725 into the account. What will his BALANCE be

mote1985 [20]

I’m not sure sorrry but i hope someone else can help u

8 0

3 years ago