Answer:
36 number of 2/3-pint bottles can be filled from a 24-pint container
Step-by-step explanation:
Volume of the container is 24 pint
Volume of the bottle is 2/3 pint
Number of 2/3 pint bottles that can be filled from 24 pint container is

36 number of 2/3-pint bottles can be filled from a 24-pint container
Ok so first multiply 4 by .25 to get 1 then 1 by 2.36 to get 2.36
This makes it easier because multiplying by 1 is easier then by a number with decimals
<h2>i cant answer it without text sorry. i just cant see the question :(</h2>
When you are multiplying an exponent directly into a number/variable with an exponent, you multiply the exponents together.
For example:


When you are multiplying a variable with an exponent by another variable with an exponent, you add the exponents together.
For example:



You multiply 3 into each exponent in the numerator and the denominator

When you have a negative exponent, you move it to the other side of the fraction to make the exponent positive.

When you have something like this:

You subtract the exponents together, so:

Your answer is the second option