19(.32) gives you 6.08 so yeahh
6.08 is 32% of 19
If

is the common difference between terms in the sequence

, then



...

You're told that

(the sum of the first 16 terms in the sequence, presumably). Well, we know that


Recall that

so that we have

So we get
Answer:
x y
-8 -2
-1 -1
0 0
1 1
8 2
Step-by-step explanation:
The given function is
![y=\sqrt[3]{x}](https://tex.z-dn.net/?f=y%3D%5Csqrt%5B3%5D%7Bx%7D)
We need to find the y-values for the given t-table.
In the given table the x-values are -8, -1, 0, 1, 8.
At x=-8,
![y=\sqrt[3]{-8}=-\sqrt[3]{2^3}=-2](https://tex.z-dn.net/?f=y%3D%5Csqrt%5B3%5D%7B-8%7D%3D-%5Csqrt%5B3%5D%7B2%5E3%7D%3D-2)
At x=-1,
![y=\sqrt[3]{-1}=-\sqrt[3]{1^3}=-1](https://tex.z-dn.net/?f=y%3D%5Csqrt%5B3%5D%7B-1%7D%3D-%5Csqrt%5B3%5D%7B1%5E3%7D%3D-1)
At x=0,
![y=\sqrt[3]{0}=0](https://tex.z-dn.net/?f=y%3D%5Csqrt%5B3%5D%7B0%7D%3D0)
At x=1,
![y=\sqrt[3]{1}=\sqrt[3]{1^3}=1](https://tex.z-dn.net/?f=y%3D%5Csqrt%5B3%5D%7B1%7D%3D%5Csqrt%5B3%5D%7B1%5E3%7D%3D1)
At x=-8,
![y=\sqrt[3]{8}=\sqrt[3]{2^3}=2](https://tex.z-dn.net/?f=y%3D%5Csqrt%5B3%5D%7B8%7D%3D%5Csqrt%5B3%5D%7B2%5E3%7D%3D2)
Therefore, the required table is:
x y
-8 -2
-1 -1
0 0
1 1
8 2
It would be china because true and false
Answer:
The following shape is not a rectangle, but a square. I know this because the length and width are the same amount of square inch(feet, what ever the square counts for on your graph.) and rectangles width are typically longer than their length. However a square shares the same length and width,
Step-by-step explanation: