Answer:
Answers are in bold type
Step-by-step explanation:
f(x) = 
The parabola opens up, so has a minimum at the vertex.
Let (h, k) be the vertex
h = -b/2a = - (-144)/2(1) = 57
k = 57^2 - 144(57) = 3249 - 6498 = -3249
Therefore, the vertex is (57, -3249)
The minimum value is -3249
The domain is the set of real numbers.
The range = {y | y ≥ -3249}
The function decreases when -∞ < x < 57 and increases when 57 > x > ∞
The x - intercepts: = 0
x(x - 114x) = 0
x = 0 or x = 114
x-intercepts are (0, 0) and (0, 114)
When x = 0, then we get the y-intercept. So, 0^2 - 114(0) = 0
y-intercept is (0, 0)
The answer is in my attachment
The required value is 8
How can we find value?
We will find the value by putting the value of w in the given function to get the required value.
We can find the value of given function foe w=2 as shown below:
Given, function is 2w+w^3-1/2w^2
Let A=2w+w^3-1/2w^2
for w=2
A=2(2)+(2)^3-1/2(2)^2
= 2+8-1/2(4)
=2+8-2
=8
Hence, the required value is 8.
Learn more about function here:
brainly.com/question/875118
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Doesn’t difference mean just to subtract the two??
If you subtract 238.3 by 45.098 you will end up with 193.202
Hope I helped you!! Brainlist will be appreciated I’m helping out a lot of people
~Indya2
Answer:
We need to sketch the problem first.
Find the size of angle R.
One member travels a distance of 12km due north. Another team member heads 50degree east of north and travels a distance of 10km.
If se substute 50° of 180 we have
180-50=130°
The distance between the two team members is the missing side.
We know two sides and included angle, so we use the cosine rule.
A2+b2+c2-2bcCosA
= 102+122-(2x10x12xcos130°)
=100+144-(-147.08)
=100+144+147.08
=391.08
A==SQRT391.08
=19.775
19.7km
Step-by-step explanation:
