Answer:
Step-by-step explanation:
4/3(6y+21)-17=43
move all terms to the left:
4/3(6y+21)-17-(43)=0
Domain of the equation: 3(6y+21)!=0
y∈R
We add all the numbers together, and all the variables
4/3(6y+21)-60=0
You multiply all the terms by the denominator
-60*3(6y+21)+4=0
multiply elements
Answer:

Step-by-step explanation:
We have
square with sides <em>s = 3cm</em>
four triangles with base <em>b = 3cm</em> and height <em>h = 9cm</em>.
The formula of an area of a square:

The formula of an area of a triangle:

Substitute:

The Surface Area:

Answer:
Option A is correct
The function
has real zeroes at x =-10 and x =-6
Explanation:
Given: The real zeroes or roots are x = -10, and x = -6
To find the quadratic function of degree 2.
where α,β are real roots. ....[1]
Here, α= -10 and β= -6
Sum of the roots:
α+β = -10+(-6) = -10-6 = -16
Product of the roots:
αβ = (-10)(-6)= 60
Substitute these value in equation [1] we have;

Therefore, the quadratic function for the real roots at x =-10 and x =-6 ;

Answer:
G
Step-by-step explanation:
difference between coordinates of A and C is 9 because 7-(-2) is 9, one-third of nine is 3, -2+3=1 G is 1. (sorry for poor phrasing)