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3 years ago

WILL UPVOTE ALL

Mathematics

1 answer:

juin [17]3 years ago

7 0

D because the others all equal to 240 but D is 200.

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Evaluate the expression

Leni [432]

$\frac{ | - 8| }{ - | - 8| } + | - 15|$
$\frac{8}{ - 8} + \frac{15}{1}$
$\frac{8 - 120}{ - 8}$
$\frac{ - 112}{ - 8}$
$14$

4 0

3 years ago

Use the disk method or the shell method to find the volumes of the solids generated by revolving the region bounded by the graph

diamong [38]

Answer:

a) 8π

b) 8/3 π

c) 32/5 π

d) 176/15 π

Step-by-step explanation:

Given lines : y = √x, y = 2, x = 0.

a) The x-axis

using the shell method

y = √x = , x = y^2

h = y^2 , p = y

vol = ( 2π ) $\int\limits^2_0 {ph} \, dy$

= $( 2\pi ) \int\limits^2_0 {y.y^2} \, dy$

∴ Vol = 8π

b) The line y = 2 ( using the shell method )

p = 2 - y

h = y^2

vol = ( 2π ) $\int\limits^2_0 {ph} \, dy$

= $( 2\pi ) \int\limits^2_0 {(2-y).y^2} \, dy$

= ( 2π ) * [ 2/3 * y^3 - y^4 / 4 ] ²₀

∴ Vol = 8/3 π

c) The y-axis ( using shell method )

h = 2-y = h = 2 - √x

p = x

vol = $(2\pi ) \int\limits^4_0 {ph} \, dx$

= $(2\pi ) \int\limits^4_0 {x(2-\sqrt{x} ) } \, dx$

= ( 2π ) [x^2 - 2/5*x^5/2 ]⁴₀

vol = ( 2π ) ( 16/5 ) = 32/5 π

d) The line x = -1 (using shell method )

p = 1 + x

h = 2√x

vol = $(2\pi ) \int\limits^4_0 {ph} \, dx$

Hence vol = 176/15 π

attached below is the graphical representation of P and h

3 0

3 years ago

It is asking what is the relationship between segment pq and p”q’

nadezda [96]

angles it sounds like but ik the struggle

7 0

3 years ago

Which situation can be represented by 12x=26.2

liraira [26]

A is the answer I would say

6 0

2 years ago

Read 2 more answers

3x~6y=~3 2x+4y=30 Elimination using multiplication

Nat2105 [25]

$\left \{ {{3x-6y=-3\ \ |*2} \atop {2x+4y=30\ \ | *(-3)}} \right. \\\\ \left \{ {{6x-12y=-6} \atop {-6x-12y=-90}} \right. \\+----\\elimination\\\\
0 \neq -69\\\\There\ are\ no\ solutions$

7 0

3 years ago