Answer:
24
Step-by-step explanation
-|-|-|-|-|-|-|-|-|-|-|-|-|-|-|-|-|-|-|-|--|-|-|-|
The last answer: 2 or 0
Explanation:
When you graph this function, it crosses the x-axis once. In other words, that means there is only 1 real zero and 2 imaginary complex zeros. In addition, imaginary solutions always come in pairs, so there can’t be a odd number of them such as 3.
If the length of a rectangle is 3m longer than its width, then:
L=W+3
Is the area really 154^2? Or is it 154m^2? If yes, then:
A=LW
154=(W+3)(W)
154=(W^2+3W)
0=W^2+3W-154
0=(W-11)(W+14)
This means either (W-11) or (W+14) is equal to zero so:
W=11 and W=-14
To find out let's substitute the numbers:
154=(11+3)(11)
154=154
Therefore, the width of the rectangle is 11m
Answer:
Test statistic = 1.664
Step-by-step explanation:
The hypothesis :
H0 : μ = 47.2
H1 : μ ≠ 47.2
Given that :
Sample mean, xbar = 47
Sample size, n = 250
Standard deviation, σ = 1.9
The test statistic :
(xbar - μ) ÷ (σ/√(n))
T = (47 - 47.2) ÷ (1.9/√(250))
T = (0.2 / 0.1201665)
Test statistic = 1.664
Answer:
its c 2b(12 - 17a)
Step-by-step explanation:
