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densk [106]
3 years ago
11

Check all that apply plz explain

Mathematics
1 answer:
JulsSmile [24]3 years ago
4 0
2 and 3 are the answers i'm pretty sure.
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Given a||b ,and cis not parallel to a or b which of the following are true ? Choose all answers that are correct.
umka2103 [35]

Answer:

Options B and D are true.

Step-by-step explanation:

See the diagram attached.

Line a and b are parallel and line c is not parallel to them.

There is a transverse line and this line forms the angles 1 to 12.

Now, option A gives ∠ 8 + ∠ 10 = 180° which can not be true as line c is not parallel to line b.

Option B gives ∠4 + ∠ 6 = 180° which is true because line a is parallel to line b and ∠ 4 and ∠ 6 are interior supplementary angles.

Option C gives ∠ 1 + ∠ 11 = 180° which can not be true as line c is not parallel to line a.

Option D gives ∠3 + ∠ 5 = 180° which is true because line a is parallel to line b and ∠ 3 and ∠ 5 are interior supplementary angles.

Therefore, options B and D are true. (Answer)

7 0
4 years ago
Need help with this (1)
attashe74 [19]
The answer, I think, is 7r/s
4 0
3 years ago
Read 2 more answers
Write each mixed number as an improper fraction. 1 7/8 1 7/12 2 1/2 NEED BRAINLIEST!!!
Alecsey [184]
15/8 19/12 5/2 is the answer for this problem 
6 0
3 years ago
CAN SOMEONE PLEASE HELP
Allushta [10]
4 is the right answer
4 0
2 years ago
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Prove that
Dovator [93]

Answer:

see explanation

Step-by-step explanation:

Using the trigonometric identities

secx = \frac{1}{cosx} , cosecx = \frac{1}{sinx}

cotx = \frac{cosx}{sinx} , tanx = \frac{sinx}{cosx}

Consider the left side

secA cosecA - cotA

= \frac{1}{cosA} × \frac{1}{sinA} - \frac{cosA}{sinA}

= \frac{1}{cosAsinA} - \frac{cosA}{sinA}

= \frac{1-cos^2A}{cosAsinA}

= \frac{sin^2A}{cosAsinA} ( cancel sinA on numerator/ denominator )

= \frac{sinA}{cosA}

= tanA = right side ⇒ proven

5 0
3 years ago
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