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MaRussiya [10]
2 years ago
8

The table shows the proof of the relationship between the slopes of two perpendicular lines. What is the missing statement in st

ep 2?

Mathematics
1 answer:
Assoli18 [71]2 years ago
5 0

Answer:

\frac{AB}{BC} = \frac{CE}{ED}

Step-by-step explanation:

Given

The attached proof

Required

Complete the missing piece

In (a), we have:

\triangle ABC \to \triangle CED

This implies that, the following sides are similar:

AB \to CE

AC \to CD

BC \to ED

An equation that compares the triangle can be any of:

\frac{AB}{BC} = \frac{CE}{ED}

\frac{AB}{AC} = \frac{CE}{CD}

.....

From the options;

\frac{AB}{BC} = \frac{CE}{ED} is true

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Seema deposited $800 in a saving account earning 2.88% compounded annually. To the nearest cent, how much will she have in 16 ye
ehidna [41]

Answer:

1260.04

Step-by-step explanation:

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5 0
3 years ago
In ΔCDE, \text{m}\angle C = (4x-16)^{\circ}m∠C=(4x−16) ∘ , \text{m}\angle D = (6x-1)^{\circ}m∠D=(6x−1) ∘ , and \text{m}\angle E
borishaifa [10]

Answer:

m∠C = 44°

Step-by-step explanation:

In ΔCDE,

m∠C=(4x−16) ∘

m∠D=(6x−1) ∘

m∠E=(4x−13) ∘ .

The sum of angles in a triangle = 180°

Step 1

We solve for x

m∠C + m∠D + m∠E

(4x−16)° + (6x−1)° + (4x−13)° = 180°

4x - 16 + 6x - 1 + 4x - 13 = 180°

4x + 6x + 4x -16 - 1 - 13 = 180°

14x - 30 = 180°

14x = 180+ 30

14x = 210

x = 210/14

x = 15

Step 2

Find m∠C

m∠C = (4x−16)°

m∠C = (4 × 15 - 16)°

m∠C = (60 - 16)°

m∠C = 44°

3 0
2 years ago
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