Answer: the average distance between the parabola is 2000
Step-by-step explanation:
Given that;
y = 30x(20 - x) and the x-axis on the interval [0, 20]
f(x) = y = 30x(20 - x); [0, 20] and a=0, b=20
the average distance between the parabola will be
Average value = 1/20-0 ²⁰∫₀ 30x(20-x) dx
= 1/20 ²⁰∫₀ (600x-30x²) dx
= 1/20 [(600x)/2 - (30x³)/3]₀²⁰
= 1/20 [300x - 10x³]₀²⁰
inputting the limits, we get
= 1/20 [(300 × 20 × 20 - 10 × 20 × 20 × 20) - 0 - 0]
= 1/20 ( 120000 - 80000)
= 0.05 × 40000
<h2>= 2000</h2>
Therefore the average distance between the parabola is 2000
<h3 />
3.937x10^-5 thats the answer..............................
The solutions would be like this for this specific problem. Please refer to the attachment below.
I am hoping that these answers have satisfied your queries and it will be able to help you in your endeavors, and if you would like, feel free to ask another question.
Answer:
It is D. ,C B
Step-by-step explanation:
Mono means single/one but binomial is only first because binomial is only (... +...)
So monomials are B,C,D