The distance d is 9 ft and the height is 12ft.
<h3>
How to find the distance and the height?</h3>
Here we can model the situation with a right triangle, where the length of the wire is the hypotenuse.
The height is one cathetus and the distance is the other catheti.
Let's define:
- h = height
- d = distance.
- hypotenuse = 15ft
We know that the height of the tower is 3 ft larger than the distance, then:
h = d + 3ft
Now we can use the Pythagorean theorem, it says that the sum of the squares of the cathetus is equal to the square of the hypotenuse.
Then:
Now we can solve this equation for d:
Then the solutions are:
We only take the positive solution:
d = (-3ft + 21ft)/2 = 9ft
And the height is 3 ft more than that, so:
h = 9ft + 3ft = 12ft
The distance d is 9 ft and the height is 12ft.
If you want to learn more about right triangles:
brainly.com/question/2217700
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<span>4 / 5 hours = 2880 seconds
hope this helps!
-Payshence xoxo</span>
Answer:
Mean and IQR
Step-by-step explanation:
The measure of centre gives the central or the measure which gives the best mid term of a distribution. Based in the details of the box plot, the median is the value which divides the box in the box plot.
For company A:
Range = 25 to 80 with a median value at 30 ; this means the median does not give a good centre measure of the distribution ad it is very close to the minimum value. This goes for the Company B plot too; with values ranging from (35 to 90) and the median designated at 40.
Hence, the mean will be the best measure of centre rather Than the median in this case.
For the variability, the interquartile range would best suit the distribution. With the lower quartile and upper quartile both having reasonable width to the minimum and maximum value of the distribution.
Answer:
(6, 6)
Step-by-step explanation:
Each grid square is 2 units. 10 units up from point P is 5 grid squares up, or 3 grid squares above the x-axis. The x-coordinate remains the same (6), and the y-coordinate is the one labeling the 3rd line above the x-axis: 6.
The coordinates of point S are (6, 6).
Answer:
3x+2y=15--------(1)
4x+2y=20--------(2)
then, 2y=15-3x------(3)
putting value of 2y in equation (2)
4x+15-3x=20
x=5
then after , putting value of x in eq(3)
y=(15-15)/2
y=0
