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ozzi
3 years ago
7

Write an equation of the line that passes through the given point and is perpendicular to the given line. 1 (-6, -4); y = 3x + 1

​
Mathematics
1 answer:
klasskru [66]3 years ago
7 0

Answer:

y= -1/3x - 6

Explain:

For the slope, you find the opposite reciprocal of the given slope. Then you plug in the given coordinates into the point-slope formula: y - y = m ( x - x ). So the expression would be y - (-4) = -1/3 ( x - (-6)). So the answer would be           y = -1/3x - 6.

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If f(x)=(2x^2)-1, find:<br> -f(3x-1)+2
Sergeeva-Olga [200]

Answer:

-f(3x - 1) + 2 = -18x² + 12x + 1

Step-by-step explanation:

Step 1: Find f(3x - 1)

f(3x - 1) = 2(3x - 1)² - 1

f(3x - 1) = 2(9x² - 6x + 1) - 1

f(3x - 1) = 18x² - 12x + 2 - 1

f(3x - 1) = 18x² - 12x + 1

Step 2: Plug in f(3x - 1)

-(18x² - 12x + 1) + 2

Step 3: Evaluate

-18x² + 12x - 1 + 2

-f(3x - 1) + 2 = -18x² + 12x + 1

8 0
3 years ago
Read 2 more answers
SAT verbal scores are normally distributed with a mean of 433 and a standard deviation of 90. Use the Empirical Rule to determin
laila [671]

34% of the scores lie between 433 and 523.

Solution:

Given data:

Mean (μ) = 433

Standard deviation (σ) = 90

<u>Empirical rule to determine the percent:</u>

(1) About 68% of all the values lie within 1 standard deviation of the mean.

(2) About 95% of all the values lie within 2 standard deviations of the mean.

(3) About 99.7% of all the values lie within 3 standard deviations of the mean.

$Z(X)=\frac{x-\mu}{\sigma}

$Z(433)=\frac{433-\ 433}{90}=0

$Z(523)=\frac{523-\ 433}{90}=1

Z lies between o and 1.

P(433 < x < 523) = P(0 < Z < 1)

μ = 433 and μ + σ = 433 + 90 = 523

Using empirical rule, about 68% of all the values lie within 1 standard deviation of the mean.

i. e. ((\mu-\sigma) \ \text{to} \ (\mu+\sigma))=68\%

Here μ to μ + σ = \frac{68\%}{2} =34\%

Hence 34% of the scores lie between 433 and 523.

8 0
3 years ago
4-(2y-1)=2(5y+9)+y please help quick
stich3 [128]

Step-by-step explanation:Step 1: Simplify both sides of the equation.

4−(2y−1)=2(5y+9)+y

4+−1(2y−1)=2(5y+9)+y(Distribute the Negative Sign)

4+−1(2y)+(−1)(−1)=2(5y+9)+y

4+−2y+1=2(5y+9)+y

4+−2y+1=(2)(5y)+(2)(9)+y(Distribute)

4+−2y+1=10y+18+y

(−2y)+(4+1)=(10y+y)+(18)(Combine Like Terms)

−2y+5=11y+18

−2y+5=11y+18

Step 2: Subtract 11y from both sides.

−2y+5−11y=11y+18−11y

−13y+5=18

Step 3: Subtract 5 from both sides.

−13y+5−5=18−5

−13y=13

Step 4: Divide both sides by -13.

−13y

−13

=

13

−13

y=−1

 Answer: y =-1

7 0
3 years ago
Read 2 more answers
Please help me thank you
gayaneshka [121]

Answer:

x = 6

Step-by-step explanation:

First, separate the problem into -\frac{2x}{3} +9=\frac{4x}{3} - 3

Then, Subtract 9 from both sides of the equation. -\frac{2x}{3} +9-9=\frac{4}{3} * x - 3-9

Simplify. -\frac{2x}{3}=\frac{4x}{3}-12

Multiply 3 to each side, which will give you -2x = 4x - 36

Subtract 4x from each side  -2x - 4x = 4x - 36x - 4x

Combine like terms: -6x = -36

Divide both sides by -6

Your answer should be 6

<em>(sorry for the late answer)</em>

5 0
3 years ago
Find the slope of line that is parallel to -2x=3y+5
In-s [12.5K]

Answer: m = -\frac{2}{3}

Step-by-step explanation:

Turn the equation into slope-intercept form: -3y = 2x + 5

Reduce: y = -\frac{2}{3}x -\frac{5}{3}

Your parallel slope is: -\frac{2}{3}

7 0
2 years ago
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