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3 years ago

8

Let l represent an infants length in excess of 50 centimeters and let w represent the median weight of female infants. Make a ta

blet paired values of l and w

1 answer:

11Alexandr11 [23.1K]3 years ago

6 0

I've seen this question before and it's word for word

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Ava has two frogs. This is 1/4 the number of frogs that Heather has. How many frogs does Heather have?

oksano4ka [1.4K]

Answer:

8

Step-by-step explanation:

2 x 4

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3 years ago

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What is the expanded form of 3x(x+2)^2

Ghella [55]

3x (x + 2)²

3x ( x² + 4)

3x³ +12x

~Hope I helped!~

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3 years ago

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Which of the equations shows an application of the Zero Property of Multiplication? A. 25+0=25 B. 13(3)= C. 0∙2=0 D. (34−2)−(34+

Montano1993 [528]

Answer:

0∙2=0

Step-by-step explanation:

Zero Property of multiplication is as follows :

The product of a number and 0 is equal to 0.

In option (c), 0 is multiplied by 2 and as a result, we get 0 as the answer.

It means,

0∙2=0

Hence, option (c) i.e. 0∙2=0 shows the Zero Property of Multiplication.

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3 years ago

HELP ASAP ILL GIVE BRAINLIST

SSSSS [86.1K]

Answer:

0.36

Step-by-step explanation:

To find the probability, just multiply.

probability of red candy * probability of pink cookie

0.9*0.4=0.36

I hope this helps!

4 0

3 years ago

Peter has 3200 yards of fencing to enclose a rectangular area. Find the dimensions of the rectangle that maximize the enclosed a

salantis [7]

Answer:

$A = 640000\,yd^{2}$

Step-by-step explanation:

Expression for the rectangular area and perimeter are, respectively:

$A (x,y) = x\cdot y$

$3200\,yd = 2\cdot (x+y)$

After some algebraic manipulation, area expression can be reduce to an one-variable form:

$y = 1600 -x$

$A (x) = x\cdot (1600-x)$

The first derivative of the previous equation is:

$\frac{dA}{dx}= 1600-2\cdot x$

Let the expression be equalized to zero:

$1600-2\cdot x=0$

$x = 800$

The second derivative is:

$\frac{d^{2}A}{dx^{2}} = -2$

According to the Second Derivative Test, the critical value found in previous steps is a maximum. Then:

$y = 800$

The maximum area is:

$A = (800\,yd)\cdot (800\,yd)$

$A = 640000\,yd^{2}$

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3 years ago

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