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-Dominant- [34]
3 years ago
12

Mary is making pillows for her life skills class.she bought 2 and 1/2 yards of fabric.herrotal cost was $15.what was the cost pe

r yard
Mathematics
1 answer:
MrRissso [65]3 years ago
7 0

Answer:

$6

Step-by-step explanation:

The answer is...

15 ÷ 2.5 = 6

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Solve the equations if possible <br><br> * -5×=×+6(1-×)<br><br> *(2×-5)²=(2×-1)(2×+1)-10(2×-1)
Allushta [10]
-5x = x + 6(1-x)

-5x = x + 6(1) + 6(-x)
-5x = x + 6 -6x
-5x = x - 6x + 6
-5x = -5x + 6
-5x + 5x = 6
0 = 6  Not equal. No solution.

(2x-5)² = (2x-1)(2x+1) -10(2x-1)
(2x-5)(2x-5) = (2x-1)(2x+1) - 20x + 10
2x(2x-5)-5(2x-5) = 2x(2x+1)-1(2x+1) - 20x + 10
4x² - 10x -10x + 25 = 4x² + 2x - 2x -1 - 20x + 10
4x² - 20x + 25 = 4x² - 20x - 1 + 10
4x² - 20x + 25 = 4x² - 20x - 9

Not equal. No solution.

8 0
3 years ago
4. Andrés desea embaldosar el piso de su casa que tiene 375 cm de ancho y 435 cm de largo. Calcula la longitud del lado que tend
svetlana [45]

Answer:

Sabemos que el piso es un rectángulo de 435 cm de largo y 375 cm de ancho.

Recordar que para un rectángulo de largo L, y ancho W, el área es:

A = L*W

Entonces el área del piso, será:

A = 435cm*375cm = 163,125 cm^2

Primero, sabemos que se utilizaran baldosas (las cuales son cuadradas) y queremos saber la longitud de lado que tendrían las baldosas.

No tenemos ningún criterio para encontrar este lado, solo que (si queremos usar un número entero de baldosas) el largo L del lado de la baldosa deberá ser un divisor de tanto el ancho como el largo del suelo.

Dicho de otra forma

el largo, 435cm, tiene que ser múltiplo de L

el ancho, 375cm, tiene que ser múltiplo de L.

Por ejemplo, ambos números son múltiplos de 5, entonces podríamos tomar L = 5cm

En este caso, el área de cada baldosa es:

a = L^2 = 5cm*5cm = 25cm^2

Y el número total de baldosas que necesitaría usar esta dado por el cociente entre el área del suelo y el area de cada baldosa.

N = ( 163,125 cm^2)/(25cm^2) = 6,525 baldosas.

También sabemos que ambos números (435cm y 375cm) son múltiplos de 15cm

Entonces las baldosas podrían tener 15cm de lado.

En este caso, el área de cada baldosa es:

A = (15cm)^2 = 225cm

En este caso el número total de baldosas necesarias será:

N =  ( 163,125 cm^2)/(225cm^2) = 725 baldosas.

5 0
3 years ago
In △ABC, AB=9.2 ft, BC=11.9 ft, and m∠B=27°.
Rashid [163]
Area of triangle = 1/2 ab sin c
Area of triangle = 1/2 (9.2)(11.9) sin (27)
Area of triangle = 24.85 ft²

-----------------------------------------------------------------------
Answer: Area - 24.85 ft²
-----------------------------------------------------------------------
3 0
3 years ago
The values of 60, 62, and 84 were common to both samples. The three values are identified as outliers with respect to the age-gr
postnew [5]

Answer:

Only 60 is an identified outlier

Step-by-step explanation:

Given

<u>Age group: 40 to 50</u>

Min = 60           Q_1 = 70           Median= 73

Q_3 = 76              Max = 85

<u>Conditions for outlier</u>

Value > Q_3 + 1.5 * IQR

Value < Q_1 - 1.5 * IQR

<em>See attachment for complete question</em>

<u>Required</u>

Which of 60, 62 and 84 is an outlier of age grout 40 to 50 years

First, calculate the IQR of group 40 to 50.

This is calculated as:

IQR = Q_3 - Q_1

Where:

Q_3 = 76 and Q_1 = 70

So:

IQR = 76 - 70

IQR = 6

<em>Next, is to test the outlier conditions on each value (i.e. 60, 62 and 84)</em>

<u></u>

<u>Testing 60</u>

<u>Condition 1</u>

Value > Q_3 + 1.5 * IQR

60 > 76 + 1.5 * 6

60 > 76 + 9

60 > 85 --- False

<u>Condition 2</u>

Value < Q_1 - 1.5 * IQR

60 < 70 - 1.5 * 6

60 < 70 - 9

60 < 61 --- True

<em>Because one of the conditions is true, then 60 is an outlier of group 40 - 50 years</em>

<em></em>

<u>Testing 62</u>

<u>Condition 1</u>

Value > Q_3 + 1.5 * IQR

62> 76 + 1.5 * 6

62 > 76 + 9

62 > 85 --- False

<u>Condition 2</u>

Value < Q_1 - 1.5 * IQR

62 < 70 - 1.5 * 6

62 < 70 - 9

62 < 61 --- False

<em>Because both conditions are false, then 62 is  not an outlier of group 40 - 50 years</em>

<em></em>

<u>Testing 84</u>

<u>Condition 1</u>

Value > Q_3 + 1.5 * IQR

84> 76 + 1.5 * 6

84 > 76 + 9

84 > 85 --- False

<u>Condition 2</u>

Value < Q_1 - 1.5 * IQR

84 < 70 - 1.5 * 6

84 < 70 - 9

84 < 61 --- False

<em>Because both conditions are false, then 84 is  not an outlier of group 40 - 50 years</em>

5 0
3 years ago
80% of 60 is 1/5 of what number?
Oksi-84 [34.3K]

Well, if 80% of 60 is 48, and 48x5 is 240, 80% of 60 is 240.

Answer: 240

Hope this helps! Xo


7 0
3 years ago
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