Correct question:
The LCM of two numbers is 9 times their HCF .The sum of LCM and HCF is 500 . Find the HCF of two numbers.
Answer:
The HCF of two numbers is 50.
Step-by-step explanation:
let the H.C.F of the two numbers = x
let the L.C.M of the two numbers = y
y = 9x -------equation (1)
y + x = 500 -------- equation (2)
y = 500 - x
Substitute in the value of y in equation (1)
500 - x = 9x
500 = 9x + x
500 = 10x
x = 500 / 10
x = 50
Therefore, the HCF of two numbers is 50.
Answer:
V =9.42 in^3
Step-by-step explanation:
The diameter is 3 inches
The radius is d/2 = 3/2 inches
The volume is
V = 4/3 pi r^2
V = 4/3 ( 3.14) ( 3/2) ^2
V =9.42 in^3
Substitute -x-2 for y in 3x+3y=6
3x+3y=6
3x+3(-x-2)=6
-6=6 (Simplify both sides of the equation)
-6+6=6+6 ( add six to both sides)
0=12
Answer: No Solutions
Hope this helped
Answer:
5cm
Step-by-step explanation:
To find the missing side we use the hypotenuse theorem.
a^2 + b^2 = c^2
The longest side of the triangle would be c. So substitute the numbers into the variables.
a^2 + 12^2 = 13^2
a^2 = 13^2 - 12^2
a^2 = 169 - 144
a^2= 25
a = √25
a=5
The missing leg's length is 5cm
First isolate y by adding x to both sides in y-x=3 and getting y=x+3
Step 1: substitute x+3 for y in 3y=x+6 to get 3(x+3)=x+6
Step 2: distribute 3x+9=x+6
Step 3: subtract like terms 2x=-3
Step 4: divide x=-3/2
substitute -3/2 for x in y=x+3 to get
y=-3/2+3
y=3/2
answer: y=3/2 x=-3/2