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Sladkaya [172]
3 years ago
7

What is the difference in the areas of a square and rectangle if the rectangle has side lengths 2 less and 2 more than

Mathematics
1 answer:
kirill [66]3 years ago
4 0

Answer:

A(square) = x*x= x^2

A(rectangle) = (a-2) (a+2) = a^2 +2a- 2a-4 = a^2 -4

A(rectangle) = A(square) -4

Step-by-step explanation:

For this case we assume that the square have sides of length x.

So then the area for this square is given by A(square) = x*x= x^2

We have a rectangle and on this case we have this information :" the rectangle has side lengths 2 less and 2 more than  a square"

So then the sides of the rectangle needs to have lengths a-2 and a+2, and if we find the area for the rectangle we got:

A(rectangle) = (a-2) (a+2) = a^2 +2a- 2a-4 = a^2 -4

And as we can see th area for the rectangl is 4 units less than the area for the rectangle:

A(rectangle) = A(square) -4

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Answer:

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Step-by-step explanation:

14y+82=6x-20

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Sub y=25 into 14y+82=6x-20

14y+82=6x-20

14(25)+82=6x-20

Calculate as follows:

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Divide both sides by 6

452=6x

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