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allochka39001 [22]
3 years ago
12

Find the Volume, Of the shape

Mathematics
1 answer:
OleMash [197]3 years ago
8 0

Answer:

V≈20.94

Step-by-step explanation:

The formula for solving the volume of a cone is V=πr^2(h/3).

Hope this helps and I hope u have an Amazing day!!

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Simplify -13.5a+34.12b+65.5-32.5b-35.8a
4vir4ik [10]

Answer:-49.3a-1.62b+65.5

Step-by-step explanation:

Combine Like terms:

-13.5a-35.8a=-49.3a

-34.12b+32.5b=-1.62b

Answer: -49.3a-1.62b+65.5

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Step-by-step explanation:

I’m srry just need points so…

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PLZ HELP HURRY!!! HAVE A DEADLINE!!!
Lynna [10]

Answer:

y = -2x - 6

The y-intercept will be (0,-6)

One point will be at (1,-8)

The line will go downward since it is a negative slope

Step-by-step explanation:

y−2=−2(x+4)

Distribute

y - 2 = -2x - 8

Move the constant to the other side

y - 2 = -2x - 8

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y = -2x - 6

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4 years ago
Find the inequality represented by the graph.
sweet-ann [11.9K]

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x > 3

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dotted line = > or <

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Triangle A"B"C" is formed using the translation (x + 2 y + 0) and the dilation by a scale factor of from the origin. Which equat
kramer

Answer:

segment a double prime b double prime = segment ab over 2

Step-by-step explanation:

Triangle A″B″C″ is formed using the translation (x + 2, y + 0) and the dilation by a scale factor of one half from the origin. which equation explains the relationship between segment ab and segment a double prime b double prime?

coordinate plane with triangle ABC at A (- 3,  3), B (1, - 3), and C (- 3, -3).

segment a double prime b double prime = segment ab over 2

segment ab = segment a double prime b double prime over 2

segment ab over segment a double prime b double prime = one half

segment a double prime b double prime over segment ab = 2

Answer:  If triangle ABC at A (- 3,  3), B (1, - 3), and c (- 3, -3) is translated using   (x + 2, y + 0), then the new coordinates of triangle ABC would be at A'(- 3 + 2,  3), B'(1 + 2, - 3), and C'(- 3 + 2, -3) Which is A'(- 1,  3), B'(3, - 3), and C'(- 1, -3). The dilation by a scale factor of from the origin gives A″ (-1/2, 3/2), B″ (3/2, -3/2) and C″(-1/2, -3/2) = (-0.5, 1.5), B″ (1.5, -1.5) and C″(-0.5, -1.5)

The distance AB and A"B" are given as:

AB=\sqrt{(1-(-3))^2+(-3-3)^2} =\sqrt{5 2} \\\\A"B"=\sqrt{(1.5-(-0.5))^2+(-1.5-1.5)^2} =\sqrt{13}

AB = √52 = √(4×52) = 2√13 = 2A"B"

A"B" = AB/2

3 0
3 years ago
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