Answer:
513.247
Step-by-step explanation:
Answer:
The answer is the option C
cube root of 
Step-by-step explanation:
Remember that
![a^{\frac{x}{y}} =\sqrt[y]{a^{x}}](https://tex.z-dn.net/?f=a%5E%7B%5Cfrac%7Bx%7D%7By%7D%7D%20%3D%5Csqrt%5By%5D%7Ba%5E%7Bx%7D%7D)
in this problem we have

therefore
![2^{\frac{4}{3}} =\sqrt[3]{2^{4}}=\sqrt[3]{16}](https://tex.z-dn.net/?f=2%5E%7B%5Cfrac%7B4%7D%7B3%7D%7D%20%3D%5Csqrt%5B3%5D%7B2%5E%7B4%7D%7D%3D%5Csqrt%5B3%5D%7B16%7D)
154 yd ²
the formula is (b • h) / 2 = A
so plug it in (14 • 22) / 2 = 154
The row echelon form of the matrix is presented as follows;

<h3>What is the row echelon form of a matrix?</h3>
The row echelon form of a matrix has the rows consisting entirely of zeros at the bottom, and the first entry of a row that is not entirely zero is a one.
The given matrix is presented as follows;

The conditions of a matrix in the row echelon form are as follows;
- There are row having nonzero entries above the zero rows.
- The first nonzero entry in a nonzero row is a one.
- The location of the leading one in a nonzero row is to the left of the leading one in the next lower rows.
Dividing Row 1 by -3 gives:

Multiplying Row 1 by 2 and subtracting the result from Row 2 gives;

Subtracting Row 1 from Row 3 gives;

Adding Row 2 to Row 3 gives;

Dividing Row 2 by -2, and Row 3 by 18 gives;

The above matrix is in the row echelon form
Learn more about the row echelon form here:
brainly.com/question/14721322
#SPJ1
6 3/4=6*4+3/4=24+3/4=27/4
z/12=27/4
4z=27*12
4z=324
z=81