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joja [24]
3 years ago
6

Please help me with this questionnn

Mathematics
1 answer:
Llana [10]3 years ago
6 0

Answer:

V = 1436.76

Step-by-step explanation:

<u>Formula:</u>

V = 4/3πr³

<u>Given:</u>

r = 7

<u>Work:</u>

V = 4/3πr³

V = 4/3π(7³)

V = 4/3π(343)

V = 1436.76

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Okay I think there has been a transcription issue here because it appears to me there are two answers. However I can spot where some brackets might be missing, bear with me on that.

A direct variation, a phrase I haven't heard before, sounds a lot like a direct proportion, something I am familiar with. A direct proportion satisfies two criteria:

The gradient of the function is constant s the independent variable (x) varies

The graph passes through the origin. That is to say when x = 0, y = 0.

Looking at these graphs, two can immediately be ruled out. Clearly A and D pass through the origin, and the gradient is constant because they are linear functions, so they are direct variations.

This leaves B and C. The graph of 1/x does not have a constant gradient, so any stretch of this graph (to y = k/x for some constant k) will similarly not be direct variation. Indeed there is a special name for this function, inverse proportion/variation. It appears both B and C are inverse proportion, however if I interpret B as y = (2/5)x instead, it is actually linear.

This leaves C as the odd one out.

I hope this helps you :)
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3 years ago
[finshed of resenct] which answer is another way to write the number of coins than hanna has [answers] 180 118 18 10
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Tom's toy box is shown below. The toy box is shaped like a rectangular prism. It has 5 wooden faces and is open on the top. What
mihalych1998 [28]

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Area of bottom:  20 x 10 = 200

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Dalton built a linear model to show the height of a meteor falling to the Earth. The meteor starts at 100 km above the Earth's s
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Answer:

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Step-by-step explanation:

The given parameters from the question are;

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The rate at which the meteor falls = 20 km per second

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Therefore, the domain represent the time it takes the meteor to reach the given 100 km height above the Earth's surface

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