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2 years ago

Kdyknuokknhnonn :) if you get this imma marry you right here right now.

Mathematics

1 answer:

Annette [7]2 years ago

8 0

Answer:

its mean marry me right here right now

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Which of the following equations could be used to determine the value of X

Tcecarenko [31]

Answer:

Step-by-step explanation:

If the original price is x and you deduct 3, you'l have x - 3.

If you buy 4 of them, you multiply that price by 4, giving you 4(x - 3).

Then, if that value is equal to 27, you get 4(x - 3) = 27

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2 years ago

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3 times the difference between ten times a number and three is eighty one? Find the number

bixtya [17]

{x 187394hours ,243}

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2 years ago

Solve the following system by graphing.

Masja [62]

Hello :
the solution is : <span>(3, -1)
put x= 3 and y = -1
you have : 3-(-1) = 4 and 3+(-1) = 2 ..... right</span>

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2 years ago

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Solve the given initial-value problem. the de is of the form dy dx = f(ax + by + c), which is given in (5) of section 2.5. dy dx

shutvik [7]

$\dfrac{\mathrm dy}{\mathrm dx}=\cos(x+y)$

Let $v=x+y$ , so that $\dfrac{\mathrm dv}{\mathrm dx}-1=\dfrac{\mathrm dy}{\mathrm dx}$ :

$\dfrac{\mathrm dv}{\mathrm dx}=\cos v+1$

Now the ODE is separable, and we have

$\dfrac{\mathrm dv}{1+\cos v}=\mathrm dx$

Integrating both sides gives

$\displaystyle\int\frac{\mathrm dv}{1+\cos v}=\int\mathrm dx$

For the integral on the left, rewrite the integrand as

$\dfrac1{1+\cos v}\cdot\dfrac{1-\cos v}{1-\cos v}=\dfrac{1-\cos v}{1-\cos^2v}=\csc^2v-\csc v\cot v$

Then

$\displaystyle\int\frac{\mathrm dv}{1+\cos v}=-\cot v+\csc v+C$

and so

$\csc v-\cot v=x+C$

$\csc(x+y)-\cot(x+y)=x+C$

Given that $y(0)=\dfrac\pi2$ , we find

$\csc\left(0+\dfrac\pi2\right)-\cot\left(0+\dfrac\pi2\right)=0+C\implies C=1$

so that the particular solution to this IVP is

$\csc(x+y)-\cot(x+y)=x+1$

5 0

2 years ago

Can I please get help with this?

Andrei [34K]

Answer: x = 20.

Step-by-step explanation:

x and (3x + 10) combine to form a right angle, shown in the diagram by the small square joining the perpendicular lines.

Right angles are 90 degrees, so you can add both angles to get 90:

$x + (3x + 10) = 90\\\\4x + 10 = 90\\\\4x = 80\\\\x = 20$

7 0

2 years ago