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dem82 [27]
3 years ago
13

7x - 3y + 12z This is algebra and I’m really bad at it

Mathematics
1 answer:
aalyn [17]3 years ago
3 0
Wait, this is simplified because there are no common terms.
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24 POINTS PLEASE
Alenkasestr [34]

Answer:

2.5X=1.0 try this i think

Step-by-step explanation:

tRY THAT

4 0
3 years ago
ok more of a question not like a equation or anything but when do you know when there is a extraneous answer and how do you solv
Likurg_2 [28]

One can know if an equation is extraneous if after plugging it in the original equation, it shows a false meaning or the value is undefined.

<h3>What is an extraneous equation?</h3>

It should be noted that an extraneous equation means a root of a transformed equation that isn't the root of the original equation due to the fact that it's excluded from the domain of the original equation.

In this case, one can know if an equation is extraneous if after plugging it in the original equation, it shows a false meaning or the value is undefined.

Learn more about equations on:

brainly.com/question/2972832

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5 0
2 years ago
What is the order of the following numbers from LEAST to GREATEST?
emmasim [6.3K]

Answer:

It is the first answer

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Find the quotient and reminder: 2,697/12
Lelechka [254]

Answer:

224 with a remainder of 9

4 0
3 years ago
Read 2 more answers
How to solve for shaded area
tamaranim1 [39]

Answer:

(a)  12.96 ft²

(b)  21.5 in²

Step-by-step explanation:

(a) For the first diagram

Area of the shaded region (A) = Area of Tripezium- area of circle

A = [1/2(a+b)h]-[πr²]............... Equation 1

Where a and b are the parallel side of the tripezium respectively, h = height of the tripezium, r = radius of the circle.

From the diagram,

Given: a = 15 ft, b = 6 ft, h = 12 ft, r = h/2 = 12/2 = 6 ft.

Constant: π = 3.14

Substitute these values into equation 1

A = [12(15+6)/2]-(3.14×6²)

A = 126-113.04

A = 12.96 ft²

(b) For the second diagram,

Area of the shaded region (A') = Area of square- area of circle

A' = (L²)-(πr²)............. Equation 2

Where L = lenght of one side of the square, r = radius of the circle

From the diagram,

Given: L = 2r = (2×5) = 10 in, r = 5 in

Substitute these values into equation 2

A' = (10²)-(3.14×5²)

A' = 100-78.5

A = 21.5 in²

5 0
3 years ago
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