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vesna_86 [32]
3 years ago
11

Kai needs to replace the strip laminate that is glued to the vertical faces on a square tabletop. The tabletop is 1.69 m2. What

length i laminate does he need
Mathematics
2 answers:
Eduardwww [97]3 years ago
6 0

Answer:

he needs 1.3 meters of laminate for the length

Step-by-step explanation:

area of a square = side multiplied by side (or length x width)

area = 1.69 m²

Length = √area of square

L = √1.69 m² or 1.3m

son4ous [18]3 years ago
5 0

Area of a square = Side x Side (length x width)

A = 1.69 m²

Length = √area of square

L = √1.69 m²

L = 1.3 m

Check Work: 1.3² = 1.3 m x 1.3m

= 1.69 m²

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If you say 3.5 times 30 ur answer would be 105
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3 years ago
Product A requires 5 machine hours per unit to be produced, Product B requires only 3 machine hours per unit, and the company's
Lesechka [4]

Answer:

  Produce only Product B.

Step-by-step explanation:

The contribution margin per machine hour for product A is ...

  ($16 -$6)/(5 hour) = $2 per hour

The contribution margin per machine hour for product B is ...

  ($12 -$5)/(3 hour) ≈ $2.33 per hour

The company should produce the maximum possible number of the product that contributes the most per machine hour: Product B.

5 0
3 years ago
Given that e= 2i – 5j + 9k and f= 8i + 15j + k, find 3f – 2e.
ipn [44]

Plug in "8i + 15j + k" for "f", and "2i – 5j + 9k" for "e"

3(8i + 15j + k) - 2(2i – 5j + 9k)

Distribute 3 to (8i + 15j + k) & - 2 to (2i – 5j + 9k)

3(8i + 15j + k) = 24i + 45j + 3k

-2(2i - 5j + 9k) = -4i + 10j - 18k

-------------------------------------------------------------------------------------------------------------------

Simplify. Combine like terms

24i - 4i + 45j + 10j + 3k - 18k

(24i - 4i) + (45j + 10j) + (3k - 18k)

20i + 55j - 15k is your answer, or (C)

-------------------------------------------------------------------------------------------------------------------

hope this helps

5 0
3 years ago
Read 2 more answers
Problem The gift shop at a science museum sells lollipops that are made to look like the planets. Each lollipop is shaped like a
Gre4nikov [31]
The volume is about 7234.56 cubic mm.

I assume the radius is 12 mm, it must have been repeated accidentally.

To find the volume of a sphere, we cube the radius, multiply by pi and finally multiply by 4/3.

We are the steps:

(12^3) = 1728 x pi (3.14)  = 5425.92 x (4/3) = 7234.56
6 0
3 years ago
Read 2 more answers
⊙O and ⊙P are given with centers (−2, 7) and (12, −1) and radii of lengths 5 and 12, respectively. Using similarity transformati
goldenfox [79]

Answer:

Whereby circle \bigodotP can be obtained from circle \bigodotO by applying the transformations of a translation of T₍₁₄, ₋₈₎ followed by a dilation by a scale factor of 2.4, \bigodotO is similar to \bigodotP

Step-by-step explanation:

The given center of the circle \bigodotO = (-2, 7)

The radius of \bigodotO, r₁ = 5

The given center of the circle \bigodotP = (12, -1)

The radius of \bigodotP, r₂ = 12

The similarity transformation to prove that \bigodotO and \bigodotP are similar are;

a) Move circle \bigodotO 14 units to the right and 8 units down to the point (12, -1)

b) Apply a scale of S.F. = r₂/r₁ = 12/5 = 2.4

Therefore, the radius of circle \bigodotO is increased by 2.4

We then obtain \bigodotO' with center at (12, -1) and radius r₃ = 2.4×5 = 12 which has the same center and radius as circle \bigodotP

∴ Circle \bigodotP can be obtained from circle \bigodotO by applying similarity transformation of translation of T₍₁₄, ₋₈₎ followed by a dilation by a scale factor of 2.4, \bigodotO is similar to \bigodotP.

7 0
3 years ago
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