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raketka [301]
2 years ago
5

Show that (0, 0) is equidistant from (1, 2), (-1, -2) and (2, 1).​

Mathematics
1 answer:
Len [333]2 years ago
3 0

Step-by-step explanation:

1) if (0;0) if point A, (1;2) is point B; (-1;-2) is C, (2;1) is D, then

2) the vector AB is (1;2); vector AC is (-1;-2) and vector AD is (2;1), then

3) the length of AB, AC and AD are:

|AB|=\sqrt{1^2+2^2}=\sqrt{5};

|AC|=\sqrt{(-1)^2+(-2)^2}=\sqrt{5};

|AD|=\sqrt{2^2+1^2}=\sqrt{5}.

4) if the lengths above are equal, then it means that (0, 0) is equidistant from (1, 2), (-1, -2) and (2, 1).

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Orlov [11]

Answer:

The Proof with Figure, Statement and Reasons is given below.

Step-by-step explanation:

Given:

∠DAF ≅ ∠EBF,

DF ≅  FE

Prove:

Δ ADF ≅ Δ BFE

Proof:

       Statements                                 Reasons

a. ∠DAF ≅ ∠EBF       ...........................Given

<u>48. ∠DFA ≅ ∠EFB  </u>..........................Vertical Angles are congruent

DF ≅  FE                 ..........................<u>.49. Given</u>

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3 years ago
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Alex73 [517]

Answer:

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4 0
3 years ago
Read 2 more answers
Modeling Exponential Growth and Decay In Exercises 119 and 120, Find the exponential function
Lubov Fominskaja [6]

Answer:

There is no exponential function passing through (1,1) and (5,5).

Step-by-step explanation:

We have the following exponential function

y = Ce^{kt}

The function passes through these two points:

(1,1): This means that when t = 1, y = 1

(5,5): This means that when t = 5, y = 5.

So

(1,1)

y = Ce^{kt}

Ce^{k} = 1

e^{k} = \frac{1}{C}

(5,5)

y = Ce^{kt}

5Ce^{k} = 1

Ce^{k} = \frac{1}{5}

From above, we have that:

e^{k} = \frac{1}{C}

C\frac{1}{C} = \frac{1}{5}

1 = \frac{1}{5}

1 cannot be equal to 1/5, so this is wrong.

This means that there is no exponential function passing through (1,1) and (5,5).

5 0
3 years ago
50 points to whoever can answer!​
Pavlova-9 [17]

Answer:

D

Step-by-step explanation:

I think I'm not sure about that

4 0
3 years ago
PLEASE ANSWER ALL BIG REWARD
sleet_krkn [62]

Answer:

  1. multiplying
  2. similar figures
  3. scale factor
  4. (x, y) (–3x, –3y) and (x, y) (0.23x, 0.23y)
  5. (x, y) --> (2x, 4y)
  6. Need diagram
  7. A. The line segment has become longer with endpoints D' (-12, -10) and E' (6 -8).
  8. Need image
  9. Reduction
  10. Enlargement

<em>good luck, i hope this helps :)</em>

6 0
3 years ago
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