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raketka [301]
2 years ago
5

Show that (0, 0) is equidistant from (1, 2), (-1, -2) and (2, 1).​

Mathematics
1 answer:
Len [333]2 years ago
3 0

Step-by-step explanation:

1) if (0;0) if point A, (1;2) is point B; (-1;-2) is C, (2;1) is D, then

2) the vector AB is (1;2); vector AC is (-1;-2) and vector AD is (2;1), then

3) the length of AB, AC and AD are:

|AB|=\sqrt{1^2+2^2}=\sqrt{5};

|AC|=\sqrt{(-1)^2+(-2)^2}=\sqrt{5};

|AD|=\sqrt{2^2+1^2}=\sqrt{5}.

4) if the lengths above are equal, then it means that (0, 0) is equidistant from (1, 2), (-1, -2) and (2, 1).

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Angle APR is vertical with Angle SPL. If Angle APR = 13x - 30, and Angle SPL = 3x + 70, what is the value of x?
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Answer:

The value of x is 10.

Step-by-step explanation:

If APR and SPL are vertical angles, then we get that \angle APR = \angle SPL. Given that \angle APR = 13\cdot x -30 and \angle SPL = 3\cdot x + 70, we find that the value of x is:

13\cdot x - 30 = 3\cdot x +70

10\cdot x = 100

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The value of x is 10.

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Answer:

y  = 112

Step-by-step explanation:

If  y varies directly as the square of x

mathematically;

y ∝ x²

y = kx² where 'k' is the constant of proportionality

let u know the value of k for this equation by making k the subject of the formular from y = kx²

divide both sides by x²

k = y / x²

given that  y = 567 x = 9

k = 567/(9)²

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3 years ago
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3 years ago
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x1 is the x coordinate. In this case it is 0.

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