Answer:
![y = 2( {3}^{x + 2} ) \: or \: y = 18( {3}^{x} )](https://tex.z-dn.net/?f=%20y%20%3D%202%28%20%7B3%7D%5E%7Bx%20%2B%202%7D%20%29%20%5C%3A%20or%20%5C%3A%20y%20%3D%2018%28%20%7B3%7D%5E%7Bx%7D%20%29)
Step-by-step explanation:
The given ordered pair is (2,162)(3,486).
Let the equation be
![y = a {(b}^{x} )](https://tex.z-dn.net/?f=y%20%3D%20a%20%7B%28b%7D%5E%7Bx%7D%20%29)
when x=2, y=162
This gives:
![162 =a {b}^{2}](https://tex.z-dn.net/?f=162%20%3Da%20%20%7Bb%7D%5E%7B2%7D%20)
Also when x=3, y=486,
![486=a {b}^{3}](https://tex.z-dn.net/?f=486%3Da%20%7Bb%7D%5E%7B3%7D%20)
Divide the second equation by the first,
![\frac{a {b}^{3} }{a {b}^{2} } = \frac{486}{162} \\ \implies \: b =3](https://tex.z-dn.net/?f=%20%5Cfrac%7Ba%20%7Bb%7D%5E%7B3%7D%20%7D%7Ba%20%7Bb%7D%5E%7B2%7D%20%7D%20%20%3D%20%20%5Cfrac%7B486%7D%7B162%7D%20%20%5C%5C%20%20%5Cimplies%20%5C%3A%20b%20%3D3%20)
When b=3, we have
![162 = a( {3}^{2} ) \\ a = \frac{162}{ {3}^{2} } \\ a = 18](https://tex.z-dn.net/?f=162%20%3D%20a%28%20%7B3%7D%5E%7B2%7D%20%29%20%5C%5C%20a%20%3D%20%20%5Cfrac%7B162%7D%7B%20%7B3%7D%5E%7B2%7D%20%7D%20%20%5C%5C%20a%20%3D%2018)
The exponential equation is:
![y = 18( {3}^{x} )](https://tex.z-dn.net/?f=y%20%3D%2018%28%20%7B3%7D%5E%7Bx%7D%20%29)
![y = 2 \times {3}^{2} ( {3}^{x} ) \\ y = 2( {3}^{x + 2} )](https://tex.z-dn.net/?f=y%20%3D%202%20%5Ctimes%20%20%7B3%7D%5E%7B2%7D%20%28%20%7B3%7D%5E%7Bx%7D%20%29%20%5C%5C%20y%20%3D%202%28%20%7B3%7D%5E%7Bx%20%2B%202%7D%20%29)
Answer:
b
Step-by-step explanation:
In a parralel graph, the slopes would always be the same. The intercept in the answer is 2, showing that the coordinate points are (0,2)
Hope this helps!:)
Answer:
idek
Step-by-step explanation:
Answer:
The correct option is 2.
Step-by-step explanation:
We know that first quartile represents the 25% of the data. Similarly median is 50% and third quartile is 75% of the data set.
So, 50% data lies between lower limit and median, first quartile and third quartile, median and upper limit.
From the given figure it is noticed that
![\text{Lower Limit}=0](https://tex.z-dn.net/?f=%5Ctext%7BLower%20Limit%7D%3D0)
![Q_1=2](https://tex.z-dn.net/?f=Q_1%3D2)
![\text{Median}=6](https://tex.z-dn.net/?f=%5Ctext%7BMedian%7D%3D6)
![Q_3=8](https://tex.z-dn.net/?f=Q_3%3D8)
![\text{Upper Limit}=9](https://tex.z-dn.net/?f=%5Ctext%7BUpper%20Limit%7D%3D9)
Therefore the 50% of the data fall between 0 and 6, 2 and 8, 6 and 9.
Since 0 and 6, 6 and 9 are not in the options, therefore 2 and 8 is correct. Option 2 is correct.
50 percent out of 80 is 40