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Angelina_Jolie [31]
2 years ago
11

Let $P$ be the set of $42^{\text{nd}}$ roots of unity, and let $Q$ be the set of $70^{\text{th}}$ roots of unity. How many eleme

nts do $P$ and $Q$ have in common
Mathematics
1 answer:
klio [65]2 years ago
8 0

Answer:

The answer to the given question can be defined as follows:

Step-by-step explanation:

\to GCF(42, 70) = 7

Therefore, the common roots of unity were  

\to e^{\pm i 2\pi \frac{k}{7}}\\\\\ where \\ \\ k=0,1,...... 6

That's why the  answer is 14 for these

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so
4 exams, so there are 4 values
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the sum is the known+unknwon
sum=76+99+86+x

so
90<span><</span>average and average <span><</span>100
or
90<span><</span>average<span><</span>100


lets say average=a

a=sum/number
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90<(76+99+86+x)/4<100
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90<span><</span>(76+99+86+x)/4
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(76+99+86+x)/4<u><</u>100
times 4 both sides
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minus 261 both sides
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so

99<u><</u>x<u><</u>139
since max score is 100
99<u><</u>x<u><</u>100

interval notaion is
[99,100]


answer is 2nd one


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Answer:

Q7. 11.3 inches (3 s.f.)

Q8. 96.2 ft

Q9. 36.4cm

Step-by-step explanation:

Q7. Please see attached picture for full solution.

Q8. Let the length of a side of the square be x ft.

Applying Pythagoras' Theorem,

34^{2}  =  {x}^{2}  +  {x}^{2}  \\ 2 {x}^{2}  = 1156 \\  {x}^{2}  = 1156 \div 2 \\  {x}^{2}  = 578 \\ x =  \sqrt{578}  \\

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