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2 years ago

I need help almost ASAP!!! 1-5

Mathematics

2 answers:

alekssr [168]2 years ago

8 0

1. $325 2. $315,000 3.$2,600 4.$6,00 5.i don’t know

ra1l [238]2 years ago

4 0

1:$325
2: 315,000
3:2,600
4:6,000
5: I’m not sure but I’ll let it know if I get the answer

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Please help me on this one thx i really need this one.

MrRissso [65]

Answer:

6 meters

Step-by-step explanation:

Every 7 floors, it goes up by 22.4 meter intervals.

Let's count down,

the 7th floor would be 50.8 - 22.4, which is 28.4.

the 0th floor would be 28.4 - 22.4, which is 6.

7 0

2 years ago

Read 2 more answers

Calculus 3 help please.

Reptile [31]

I assume each path $C$ is oriented positively/counterclockwise.

(a) Parameterize $C$ by

$\begin{cases} x(t) = 4\cos(t) \\ y(t) = 4\sin(t)\end{cases} \implies \begin{cases} x'(t) = -4\sin(t) \\ y'(t) = 4\cos(t) \end{cases}$

with $-\frac\pi2\le t\le\frac\pi2$ . Then the line element is

$ds = \sqrt{x'(t)^2 + y'(t)^2} \, dt = \sqrt{16(\sin^2(t)+\cos^2(t))} \, dt = 4\,dt$

and the integral reduces to

$\displaystyle \int_C xy^4 \, ds = \int_{-\pi/2}^{\pi/2} (4\cos(t)) (4\sin(t))^4 (4\,dt) = 4^6 \int_{-\pi/2}^{\pi/2} \cos(t) \sin^4(t) \, dt$

The integrand is symmetric about $t=0$ , so

$\displaystyle 4^6 \int_{-\pi/2}^{\pi/2} \cos(t) \sin^4(t) \, dt = 2^{13} \int_0^{\pi/2} \cos(t) \sin^4(t) \,dt$

Substitute $u=\sin(t)$ and $du=\cos(t)\,dt$ . Then we get

$\displaystyle 2^{13} \int_0^{\pi/2} \cos(t) \sin^4(t) \, dt = 2^{13} \int_0^1 u^4 \, du = \frac{2^{13}}5 (1^5 - 0^5) = \boxed{\frac{8192}5}$

(b) Parameterize $C$ by

$\begin{cases} x(t) = 2(1-t) + 5t = 3t - 2 \\ y(t) = 0(1-t) + 4t = 4t \end{cases} \implies \begin{cases} x'(t) = 3 \\ y'(t) = 4 \end{cases}$

with $0\le t\le1$ . Then

$ds = \sqrt{3^2+4^2} \, dt = 5\,dt$

and

$\displaystyle \int_C x e^y \, ds = \int_0^1 (3t-2) e^{4t} (5\,dt) = 5 \int_0^1 (3t - 2) e^{4t} \, dt$

Integrate by parts with

$u = 3t-2 \implies du = 3\,dt \\\\ dv = e^{4t} \, dt \implies v = \frac14 e^{4t}$

$\displaystyle \int u\,dv = uv - \int v\,du$

$\implies \displaystyle 5 \int_0^1 (3t-2) e^{4t} \,dt = \frac54 (3t-2) e^{4t} \bigg|_{t=0}^{t=1} - \frac{15}4 \int_0^1 e^{4t} \,dt \\\\ ~~~~~~~~ = \frac54 (e^4 + 2) - \frac{15}{16} e^{4t} \bigg|_{t=0}^{t=1} \\\\ ~~~~~~~~ = \frac54 (e^4 + 2) - \frac{15}{16} (e^4 - 1) = \boxed{\frac{5e^4 + 55}{16}}$

$\begin{cases} x(t) = 3(1-t)+t = -2t+3 \\ y(t) = (1-t)+2t = t+1 \\ z(t) = 2(1-t)+5t = 3t+2 \end{cases} \implies \begin{cases} x'(t) = -2 \\ y'(t) = 1 \\ z'(t) = 3 \end{cases}$

with $0\le t\le1$ . Then

$ds = \sqrt{(-2)^2 + 1^2 + 3^2} \, dt = \sqrt{14} \, dt$

and

$\displaystyle \int_C y^2 z \, ds = \int_0^1 (t+1)^2 (3t+2) \left(\sqrt{14}\,ds\right) \\\\ ~~~~~~~~ = \sqrt{14} \int_0^1 \left(3t^3 + 8t^2 + 7t + 2\right) \, dt \\\\ ~~~~~~~~ = \sqrt{14} \left(\frac34 t^4 + \frac83 t^3 + \frac72 t^2 + 2t\right) \bigg|_{t=0}^{t=1} \\\\ ~~~~~~~~ = \sqrt{14} \left(\frac34 + \frac83 + \frac72 + 2\right) = \boxed{\frac{107\sqrt{14}}{12}}$

8 0

1 year ago

15 POINTs_ NEED ASAP!

sleet_krkn [62]

Answer:

Step-by-step explanation:

1 TRUE

A number is always 100% Anyting bigger than 100% is going to be a bigger number

Anything smaller than 100% is a smaller number

2FALSE 5/100 = 0.05 and NOT 0.5

0.5% is the same as thalf of 100% = 50%

50/100 = 5/10 = 0.5

6 0

2 years ago

Help pls .!!!!!!!!!!!

Igoryamba

A and C are the answer

4 0

2 years ago

Read 2 more answers

1. (You may get teacher help with this during tutoring)

Nezavi [6.7K]

Answer:

1A --- 25

1B --- (5 + 4) x 2 + 6 - 2 x 2 - 1 = 19

2A --- -206

2B --- ?

3A --- 5.8 × 10⁷

3B --- 2.5 × 10⁻³

4A --- 4.67 × 10¹³

4B --- 3.5 × 10⁻³

5A --- 9 × 10⁶

5B --- 1.68 × 10¹⁰

5C --- All ants combined weigh 112.46 times more than all humans combined

Step-by-step explanation:

(I am using PEMDAS for Order of Operations)

1A -----------------------------------------------

6 × 7 - 3² × 9 + 4³

Parenthesis

No parenthesis.

Exponents

6 × 7 - 3² × 9 + 4³

6 × 7 - 9 × 9 + 64

Multiplication

6 × 7 - 9 × 9 + 64

42 - 81 + 64

Division

No division.

Addition

42 - 81 + 64 (the 81 is negative)

42 + -17

1B --------------------------------------

5 + 4 x 2 + 6 - 2 x 2 - 1 = 14

(5 + 4) x 2 + 6 - 2 x 2 - 1 = 19

9 x 2 + 6 - 2 x 2 - 1

18 + 6 - 2 x 2 - 1

18 + 6 - 4 - 1

24 - 5

2A --------------------------------------------

3 × 7 - 3³ × 9 + 4²

Parenthesis

No parenthesis

Exponents

3 × 7 - 27 × 9 + 16

Multiplication

21 - 27 × 9 + 16

21 - 243 + 16

Addition

21 - 243 + 16

21 - 227

Subtraction

21 - 227

-206

2B ---------------------------------------------

5 + 3 × 2 + 6 - 2 × 3 - 7 = 4

(sorry cant figure this one out)

3A ------------------------------------------------

Move the decimal point in 58,000,000.0 over x times until you have 5.8000000. It was moved to the left 7 times, so the answer is 5.8 × 10⁷.

3B -----------------------------------------------

Move the decimal point in 0.0025 over x times until you have 2.5. It was moved to the right 3 times, so the answer is 2.5 × 10⁻³.

4A -----------------------------------------------

Move the decimal point in 46,700,000,000,000.0 x times until you have 4.67. It was moved to the left 13 times so the answer is 4.67 × 10¹³.

4B ----------------------------------------------

Move the decimal point in 0.0035 x times until you have 3.5. It was moved to the right 3 times, so the answer is 3.5 × 10⁻³.

5A -------------------------------------------------

(4.5 × 10³)(2 × 10³)

4.5 × 2 = 9

10³ × 10³ = 10⁶

9 × 10⁶

5B ------------------------------------------------------

(1.4 × 10⁵)(1.2 × 10⁵)

1.4 × 1.2 = 1.68

10⁵ * 10⁵ = 10¹⁰

1.68 × 10¹⁰

5C ---------------------------------------------------------

An adult human is 65 kilograms.

6.5 × 10¹ grams

An ant is (you didnt say how many so im going with) 5 grams.

5 × 10⁰ grams

6.84 billion humans

6,840,000,000.0 humans

6.84 × 10⁹ humans

10,000 trillion ants

1 × 10¹⁶ ants

Weight of humans:

(6.5 × 10¹)(6.84 × 10⁹)

44.46 × 10¹⁰

All humans weigh 4.446 × 10¹¹ kilograms

Weight of ants:

(5 × 10⁰)(1 × 10¹⁶)

All ants weigh 5 × 10¹⁶ grams

1000 grams per kilogram

1000 = 1 × 10³

5 × 10¹⁶ ÷ 1 × 10³

5 ÷ 1 = 5

16 - 3 = 13

All ants weigh 5 × 10¹³ kilograms

All humans weigh 4.446 × 10¹¹ kilograms

5 × 10¹³ ÷ 4.446 × 10¹¹ = 112.46

All ants combined weigh 112.46 times more than all humans combined

7 0

3 years ago