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pochemuha
2 years ago
5

Evaluate the expression when y=-7

Mathematics
1 answer:
egoroff_w [7]2 years ago
8 0

Answer:

17

Step-by-step explanation:

Y = - 7

-7 to the 2nd power = 49.

4(-7) = - 28

49+(-28)=21

21 - 5 = 17

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7 = 3t - 3 - 2+ + 6. <br><br>Justification: ? property​
Volgvan

Answer:

7 = 3t + 1

t = 6

....................

7 = 3t - 2t + 3

t = 4

4 0
3 years ago
Suppose ΔXYZ is given, and you want to construct ΔABC so that the triangles are congruent. Which constructions would guarantee t
bekas [8.4K]

Answer:

A: constructing ΔABC so that AB ≅ XY, BC ≅ YZ, and CA ≅ ZX

C: constructing ΔABC so that AB ≅ XY, CA ≅ ZX, and ∠A ≅ ∠X

Step-by-step explanation:

* Lets revise the ways of constructing a triangle

- There are 3 ways to construct a triangle

# You must have length of one side and measures of two angles which

  are the endpoint of the side

# You must have a length of two sides and the measure of the including

  angle between the two sides

# You must have the length of the 3 sides

* Lets solve the problem

∵ Δ XYZ ≅ Δ ABC

∴ XY = AB , YZ = BC , ZX = CA

∴ m∠ X = m∠ A , m∠ Y = m∠ B , m∠ Z = m∠ C

- To construct Δ ABC You can use:

# The length of the 3 sides

∵ AB ≅ XY , BC ≅ YZ , CA ≅ ZX

∴ constructing ΔABC so that AB ≅ XY, BC ≅ YZ, and CA ≅ ZX ⇒ A

# The length of two sides and the measure of the including angle

∵ AB ≅ XY , CA = ZX

∵ The including angles between the sides are ∠A and ∠X

∴ constructing ΔABC so that AB ≅ XY, CA ≅ ZX, and ∠A ≅ ∠X ⇒ C

# The length of one side and the measures of two angles which are

   the endpoints of the side

∵ CA ≅ ZX

∵ The end points are C , A and Z , X

∴ constructing ΔABC so that CA ≅ ZX, ∠A ≅ ∠X, and ∠C ≅ ∠Z

- But this answer not in the choices

∴ The answer is A and C

4 0
3 years ago
Read 2 more answers
Which of the following proportions is false?
lesya [120]

Answer:

D is false

Step-by-step explanation:

7 0
2 years ago
Read 2 more answers
What is the percentage of 204 over 1015, 1 over 8120, 1 over 5832, and 1 over 6?
Basile [38]

Answer:

204/1015 (irreducible) = 20.1%

1/8120 (irreducible) = 0.01232%

1/5832 (irreducible) = 0.01715%

1/6 (irreducible) = 16.67%

Step-by-step explanation:

8 0
3 years ago
I would love to know how to do this
nirvana33 [79]
The answer is C .
Hope it helps
6 0
2 years ago
Read 2 more answers
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