Answer:
48sq^2
Step-by-step explanation:
(12*8)/2
96/2
48
Yes the correct answer is D. Hope this helps :)
Part a:-
The base of each triangle is 4 inches long.
Their height is 3/2 * 4 = 6 inches.
b
The combined area of the triangular faces = 4 * 1/2 * 4 * 6 = 48 sq ins
c
Surface area of the pyramid = 48 + area of base = 48 + 16 = 64 sq ins.
I'll do the first one to get you started
The equation y = x^2+16x+64 is the same as y = 1x^2+16x+64
Compare that to y = ax^2+bx+c and we see that
a = 1
b = 16
c = 64
Use the values of 'a' and b to get the value of h as shown below
h = -b/(2a)
h = -16/(2*1)
h = -8
This is the x coordinate of the vertex.
Plug this x value into the original equation to find the corresponding y value of the vertex.
y = x^2+16x+64
y = (-8)^2 + 16(-8) + 64
y = 0
Since the y coordinate of the vertex is 0, this means k = 0.
The vertex is (h,k) = (-8, 0)
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So we found that a = 1, h = -8 and k = 0
Therefore,
f(x) = a(x-h)^2 + k
f(x) = 1(x-(-8))^2 + 0
f(x) = (x+8)^2
is the vertex form
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<h3>Final answer to problem 1 is f(x) = (x+8)^2 </h3>
Answer:
17
Step-by-step explanation:
2 (4) + 6^2 / 4 = 8 + 36 / 4 = 8 + 9 = 17.
When solving these types of problems, make sure to use BEDMAS. For example, in this question, do x^2 / 4 before 2y + (x^2 / 4).
