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Artyom0805 [142]
3 years ago
6

What is the domain of the function y=7x-1

Mathematics
1 answer:
Anna007 [38]3 years ago
8 0

Answer:

Ahh I did this about a year ago but try math-way (without -) it gives the correct answers sorry I couldn't help more.

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Given the graph of the function F(x) below, what happens to F(x) when x is a
deff fn [24]

Answer:

c

Step-by-step explanation:

From the graph as x gets larger and becomes positive f(x) approaches 0 so the answer is C.

8 0
3 years ago
What is the answer to this? −1.3≥2.9−0.6r
Karolina [17]

Answer:

Inequality Form:

r ≥ 7

Interval Notation:

[7, ∞)

Step-by-step explanation:

−1.3 ≥ 2.9 − 0.6r

Rewrite so r is on the left side of the inequality.

2.9 − 0.6r  ≤ −1.3

Move all terms not containing r to the right side of the inequality.  

Subtract 2.9 from both sides of the inequality.

−0.6r  ≤ −1.3 − 2.9

Subtract 2.9 from −1.3.

−0.6r  ≤ −4.2

Divide each term by −0.6 and simplify.

      Divide each  term in −0.6r  ≤ −4.2 by −0.6. When multiplying or dividing both sides of an

      inequality by a negative value, f lip the direction of the inequality sign.

       −0.6r /−0.6 ≥  −4.2 /−0.6

       Cancel the common factor of −0.6.

                  −4.2

          r ≥    ______

                  −0.6

 Divide −4.2 by −0.6.

r ≥ 7

The result can be shown in multiple forms.

Inequality Form:

r ≥ 7

Interval Notation:

[7, ∞)

6 0
3 years ago
What should you do first in solving the quadratic equation?<br> x² + 18x + 81 = 25
N76 [4]

Answer:

x= -4,-14

Step-by-step explanation:

Try first to solve the equation by factoring. Be sure that your equation is in standard form before you start your factoring attempt.

3 0
2 years ago
Given the circle with the equation (x + 1)2 + y2 = 36, determine the location of each point with respect to the graph of the cir
kati45 [8]
\bf \textit{equation of a circle}\\\\ &#10;(x- h)^2+(y- k)^2= r^2&#10;\qquad &#10;center~~(\stackrel{}{ h},\stackrel{}{ k})\qquad \qquad &#10;radius=\stackrel{}{ r}\\\\&#10;-------------------------------\\\\&#10;(x+1)^2+y^2=36\implies [x-(\stackrel{h}{-1})]^2+[y-\stackrel{k}{0}]^2=\stackrel{r}{6^2}~~~~&#10;\begin{cases}&#10;\stackrel{center}{(-1,0)}\\&#10;\stackrel{radius}{6}&#10;\end{cases}

so, that's the equation of the circle, and that's its center, any point "ON" the circle, namely on its circumference, will have a distance to the center of 6 units, since that's the radius.

\bf ~~~~~~~~~~~~\textit{distance between 2 points}&#10;\\\\&#10;(\stackrel{x_1}{-1}~,~\stackrel{y_1}{0})\qquad &#10;A(\stackrel{x_2}{-1}~,~\stackrel{y_2}{1})\qquad \qquad &#10;%  distance value&#10;d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}&#10;\\\\\\&#10;\stackrel{distance}{d}=\sqrt{[-1-(-1)]^2+(1-0)^2}\implies d=\sqrt{(-1+1)^2+1^2}&#10;\\\\\\&#10;d=\sqrt{0+1}\implies d=1

well, the distance from the center to A is 1, namely is "inside the circle".

\bf ~~~~~~~~~~~~\textit{distance between 2 points}&#10;\\\\&#10;(\stackrel{x_1}{-1}~,~\stackrel{y_1}{0})\qquad &#10;B(\stackrel{x_2}{-1}~,~\stackrel{y_2}{6})\\\\\\&#10;\stackrel{distance}{d}=\sqrt{[-1-(-1)]^2+(6-0)^2}\implies d=\sqrt{(-1+1)^2+6^2}&#10;\\\\\\&#10;d=\sqrt{0+36}\implies d=6

notice, the distance to B is exactly 6, and you know what that means.

\bf ~~~~~~~~~~~~\textit{distance between 2 points}&#10;\\\\&#10;(\stackrel{x_1}{-1}~,~\stackrel{y_1}{0})\qquad &#10;C(\stackrel{x_2}{4}~,~\stackrel{y_2}{-8})&#10;\\\\\\&#10;\stackrel{distance}{d}=\sqrt{[4-(-1)]^2+[-8-0]^2}\implies d=\sqrt{(4+1)^2+(-8)^2}&#10;\\\\\\&#10;d=\sqrt{25+64}\implies d=\sqrt{89}\implies d\approx 9.43398

notice, C is farther than the radius 6, meaning is outside the circle, hiking about on the plane.
3 0
3 years ago
Read 2 more answers
If Jill's best friend jumped farther than 6.5 feet, then she beat the school record and
tigry1 [53]

Answer:

what is this for?

Step-by-step explanation:

BTW: 7th graders

3 0
2 years ago
Read 2 more answers
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