Answer:
Length = 40
Height = 20
Step-by-step explanation:
If you multiply 40 x 20, it equals 800
20 is also half of 40 as well.
<span>Simplifying
12 + -6(w + -3) = 3(-5 + -3w) + 21
Reorder the terms:
12 + -6(-3 + w) = 3(-5 + -3w) + 21
12 + (-3 * -6 + w * -6) = 3(-5 + -3w) + 21
12 + (18 + -6w) = 3(-5 + -3w) + 21
Combine like terms: 12 + 18 = 30
30 + -6w = 3(-5 + -3w) + 21
30 + -6w = (-5 * 3 + -3w * 3) + 21
30 + -6w = (-15 + -9w) + 21
Reorder the terms:
30 + -6w = -15 + 21 + -9w
Combine like terms: -15 + 21 = 6
30 + -6w = 6 + -9w
Solving
30 + -6w = 6 + -9w
Solving for variable 'w'.
Move all terms containing w to the left, all other terms to the right.
Add '9w' to each side of the equation.
30 + -6w + 9w = 6 + -9w + 9w
Combine like terms: -6w + 9w = 3w
30 + 3w = 6 + -9w + 9w
Combine like terms: -9w + 9w = 0
30 + 3w = 6 + 0
30 + 3w = 6
Add '-30' to each side of the equation.
30 + -30 + 3w = 6 + -30
Combine like terms: 30 + -30 = 0
0 + 3w = 6 + -30
3w = 6 + -30
Combine like terms: 6 + -30 = -24
3w = -24
Divide each side by '3'.
w = -8
Simplifying
w = -8</span>
Answer:
From -2<x<-1, the function F(X) is increasing. (B)
Really, it increases all from around -2.5<x<0.5
C is also the second answer, as it increases til around 2.5
It is decreasing from -4<x<-3. But increases right after. It then starts to slow down around x = 1 and go down again.
Which means (B) is your answer.
If you want to get fancy, its a polynomial and if you take the derivative for instantaneous rate, you will see f prime is increasing if you make an example function.
Answer:
First, third, and fourth one would be the answers.
Answer:
5091 Km/hr and 505 km/hr
Step-by-step explanation:
Speed = Distance / Time
Let the speed of first automobile be 'x' and that of the second be 'y'
Since speed of one is 10 times greater than the other. therefore;
⇒ x = 10 y
also let time for faster automobile be 'T' and time for slower auto mobile be 't'
Since first arrive one hour earlier than second, therefore;
⇒ t = T + 1
⇒ For first automobile; 
; substituting for 'x' and 'T'. Therefore;
⇒ 
⇒ For Second automobile; 
⇒ 
⇒ 
⇒ 5600 + 
= 560
⇒ 5600 - 560 = -
⇒ t = 1.11 hr
also ; T = 1.11 - 1 = 0.11 hr
Speed of 1st auto = 560/0.11 = 5091 km /hr
Speed of 2nd auto = 560/1.11 = 505 km/hr
