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igor_vitrenko [27]
3 years ago
10

If standard deviation of a given data is 5 and mean is 50 then coefficient of variation (C.V) is equal to *

Mathematics
1 answer:
torisob [31]3 years ago
4 0

Answer:

10

Step-by-step explanation:

Coefficient of variation is a measure of dispersion, showing the variability of data in relation to the mean.

The Coefficient of variation compares the degree of variation between data points. The coefficient of variation is the ratio of mean to standard deviation. It is given by the formula:

Coefficient of variation = mean / standard deviation

Coefficient of variation = 50 / 5

Coefficient of variation = 10

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What is the volume of a cylinder, in cubic centimeters, with a height of 8 centimeters
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Answer:

1608.5 cm³

Step-by-step explanation:

Use the cylinder volume formula, V = \pir²h

If the diameter is 16 cm, then the radius is 8 cm.

Plug in the radius and height into the formula, and solve:

V = \pir²h

V = \pi(8)²(8)

V = \pi(64)(8)

V = 1608.5

So, to the nearest tenth, the volume of the cylinder is 1608.5 cm³

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Find the area of rectangle $BCEF$ . Round the area to the nearest whole number, if necessary.
WINSTONCH [101]

Answer:

999

Step-by-step explanation:

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3 years ago
Does this table represent a function ? Why or why not
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Read 2 more answers
An object is heated to 100°. It is left to cool in a room that
stepladder [879]

Answer:

Step-by-step explanation:

Use Newton's Law of Cooling for this one.  It involves natural logs and being able to solve equations that require natural logs.  The formula is as follows:

T(t)=T_{1}+(T_{0}-T_{1})e^{kt} where

T(t) is the temp at time t

T₁ is the enviornmental temp

T₀ is the initial temp

k is the cooling constant which is different for everything, and

t is the time (here, it's in minutes)

If we are looking first for the temp after 20 minutes, we have to solve for the k value.  That's what we will do first, given the info that we have:

T(t) = 80

T₁ = 30

T₀ = 100

t = 5

k = ?

Filling in to solve for k:

80=30+(100-30)e^{5k} which simplifies to

50=70e^{5k} Divide both sides by 70 to get

\frac{50}{70}=e^{5k} and take the natural log of both sides:

ln(\frac{5}{7})=ln(e^{5k})

Since you're learning logs, I'm assuming that you know that a natural log and Euler's number, e, "undo" each other (just like taking the square root of something squared).  That gives us:

-.3364722366=5k

Divide both sides by 5 to get that

k = -.0672944473

Now that we have a value for k, we can sub that in to solve for T(20):

T(20)=30+(100-30)e^{-.0672944473(20)} which simplifies to

T(20)=30+70e^{-1.345888946}

On your calculator, raise e to that power and multiply that number by 70:

T(20)= 30 + 70(.260308205) and

T(20) = 30 + 18.22157435 so

T(20) = 48.2°

Now we can use that k value to find out when (time) the temp of the object cools to 35°:

T(t) = 35

T₁ = 30

T₀ = 100

k = -.0672944473

t = ?

35=30+100-30)e^{-.0672944473t} which simplifies to

5=70e^{-.0672944473t}

Now divide both sides by 70 and take the natural log of both sides:

ln(\frac{5}{70})=ln(e^{-.0672944473t}) which simplifies to

-2.63905733 = -.0672944473t

Divide to get

t = 39.2 minutes

3 0
3 years ago
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