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3 years ago

6. If xy = 6 and x = 2, then x + y =

Mathematics

1 answer:

ANTONII [103]3 years ago

6 0

Xy = 6
x = 2

2y = 6

y = 6÷2

y = 3

x + y = (2) + (3) = 5

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Can someone please solve both of these showing all the steps I'll add extra points because its two

EastWind [94]

Answer:

4. 21

5. 32

Step-by-step explanation:

First question:

sin(x) = opp/hyp = 22/63 = 0.3492

x = sin⁻¹(0.3492)

20.43. Rounded to the nearest degree, it would be 21.

Second question:

sin(x) = opp/hyp = 18/34 = 0.5294

x = sin⁻¹(0.5294)

31.96. Rounded to the nearest degree, it would be 32.

Let me know if you have any problems.

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3 years ago

Find all x and y intercepts of the graph of the function f(x)= 2x^3+6x^2-2x-6

topjm [15]

9514 1404 393

Answer:

y-intercept: (0, -6)
x-intercepts: (-3, 0), (-1, 0), (1, 0)

Step-by-step explanation:

We notice the first pair of coefficients is the same as the last pair (with the sign changed). This means we can factor by grouping.

f(x) = (2x^3 +6x^2) -(2x +6)

f(x) = 2x^2(x +3) -2(x +3)

f(x) = 2(x^2 -1)(x +3) = 2(x -1)(x +1)(x +3)

The factors are made to be zero when x is 1, -1, or -3.

The x-intercepts are (1, 0), (-1, 0), (-3, 0).

The y-intercept is the constant, -6.

4 0

3 years ago

The admission fee at an amusement park is $1.50 for children and $4 for adults. On a certain day 333 people enter the park, the

liberstina [14]

Answer:

188 children and 145 adults were admitted in the park.

Step-by-step explanation:

Given:

The admission fee at an amusement park is $1.50 for children and $4 for adults.

Total $862 collected on a certain day when 333 people enter the park.

Now, to find the children and adults admitted in the park.

Let the number of children admitted be $x.$

And the the number of adults admitted be $y.$

So, the total people enter the park:

$x+y=333\\\\x=333-y\ \ \ ...(1)$

Thus, the total amount collected of the admission fee:

$1.50(x)+4(y)=862\\\\$

Substituting the value of $x$ from equation (1):

$1.50(333-y)+4(y)=862\\\\499.50-1.50y+4y=862\\\\499.50+2.50y=862\\\\Subtracting\ both\ sides\ by\ 499.50\ we\ get:\\\\2.50y=362.50\\\\Dividing\ both\ sides\ by\ 2.50\ we\ get:\\\\y=145.$

Thus, the number of adults = 145.

Now, to get the number of children by substituting the value of $y$ in equation (1) we get:

$x=333-y\\\\x=333-145\\\\x=188.$

Hence, the number of children = 188.

Therefore, 188 children and 145 adults were admitted in the park.

4 0

3 years ago

given the rule s=t+3 and the starting number 0, create a table to show the first 5 terms in the sequence graph the resulting ord

IRINA_888 [86]

0= 3
1= 4
2=5
3=6
4=7
5=8
6=9
7=10

8 0

3 years ago

Factor y=x Squared-8x

Minchanka [31]

X²-8x
factor out x
x(x-8)
y=x(x-8)

6 0

3 years ago

6. If xy = 6 and x = 2, then x + y = ​

6. If xy = 6 and x = 2, then x + y =