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2 years ago

''A florist measures the lengths of roses. The lengths in inches of a dozen roses are given below'' I'm really confused.

Mathematics

1 answer:

alexira [117]2 years ago

3 0

Complete data:

13.5 13.5 13.25 13.0 13.25 13.5 13.0 13.25 13.0 13.25 12.75 12.75 Part A How many dots should go above each data value in the line plot? Type a number in each box

Answer:

12.75 ___ 2 dots

13.0 ____ 3 dots

13.25 ___ 4 dots

13.5 ___ 3 dots

Step-by-step explanation:

Given the data :

13.5 13.5 13.25 13.0 13.25 13.5 13.0 13.25 13.0 13.25 12.75 12.75

To know the Number of dots for each data value, we obtain the frequency of each data value ;

Length of Rose____ Frequency

12.75 _________:__ 2

13.0 ____________ 3

13.25 ___________ 4

13.5 ____________ 3

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Melissa's Coffee Shop makes a blend that is a mixture of two types of coffee. Type A coffee costs Melissa $4.35 per pound, and t

ehidna [41]

Answer:

well let’s break this down

Let’s make type a coffee “a”

And type b coffee “b”

a is 4.35

b is 5.70

We knwo that b is twice as many as a

The total is 614.25

So we can do soemthing like this

4.35a+ (5.70b)2 = 614.25

Now solve

If we simplify its really

4.35a+11.40b =614.25

I like multiply by a 100 to get rid of decimals

435a+1140b=61425

Here we can go 2 ways

We can isoalte a or b

im gonna isloate b

so it would be (61425-435a)/1140 =b

Now we can use that as a subsitube to find a

Now we can just do this

435a +1140(61425-435a)/1140 = 61425

Pop it through an algebra calculator (just search up math pa..Pa and copy paste it, edit if needed) and then you’d get your answer

8 0

3 years ago

Pls help me with trig :)

trapecia [35]

Answer:

Step-by-step explanation:

let ∠GEF=x

then ∠GFE=90-x

$\frac{GH}{EH}=tan x\\GH=EH~ tan x\\or~ GH=a ~tan x=6 tan x\\\frac{GH}{FH}=tan (90-x)=cot x\\GH=FH*cot x\\GH=b*cot x=27 cot x\\6 tan x=27 cotx\\\frac{tan x}{cot x}=\frac{27}{6}\\tan ^2 x=\frac{27}{6}=\frac{9}{2}\\sec^2x-tan^2x=1\\sec^2 x=1+tan ^2x=1+\frac{9}{2}=\frac{11}{2}\\\frac{EG}{EH}=sec x\\ EG=EH sec x=a sec x= 6 sec x=6\sqrt{\frac{11}{2} } =3\sqrt{22} \approx 14.07$