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Helga [31]
3 years ago
6

Come up with a new linear function that has a slope that falls in the range −1< m< 0 . Choose two different initial values

. For this new linear function, what happens to the function’s values after many iterations? Are the function’s values getting close to a particular number in each case?
Mathematics
2 answers:
katovenus [111]3 years ago
8 0

5. The slopes approach negative infinity.

#6 was skipped for my teacher.

Question 7 follows a pattern with answers:

3.4

1.2

2.4

3.2

1.6

3.2

1.6 which is the loop

8. Question 8 answers

3.44

1.12

2.24

3.52

0.96

1.92

3.84*

0.32

0.64

1.28

2.56

2.88

2.24

-2.48

3.04

1.92

3.84*

0.32*

Which is the loop.

Problems with answers like this make me wonder if something is wrong with my Algebra 2 teacher, or if he is just mean. One little mistake and you would never find the answer.

9-11 were skipped.

aleksklad [387]3 years ago
7 0
Answer:

1) After many iterations the function will become negative (at some moment)

2) The values are not getting close to a particular number; they will be decreasing indefinetly (toward - ∞)

Justification:

1) You can choose any value of the slope,m, in the interval (-1,0)

2) Use, for example, m = - 1/2

3) Since the slope intercept form of the linear equation is y = mx + b, you have your equation is:

y = (-1/2)x + b

4) That means that for any consecutive itereation the value of the function f, will decrease 1/2.

Suppose that you start with a value y = 1

Then, the next value will be y = 1 - 1/2 = 1/2

The next value will be y = 1/2 - 1/2 = 0

The next value will be y = 0 - 1/2 = -  1/2.

And so on.

The value of y will be decreasing with each iteration. The function f has not limit when x approaches bigger values, it will always become smaller and smalller.

Mathematically, it is said that the limit of function f(x) and x approaches zero is negative infinity.
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Manuel bought a balloon (that is a perfect sphere) with a radius of 2 \text{ cm}2 cm2, space, c, m. He wanted his balloon to be
jonny [76]
The original volume of the balloon is given by:
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 Where,
 r: radius of the sphere.
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 V1 = (4/3) * (pi) * (1 ^ 3)
 V1 = (4/3) * (pi) * (1)
 Then, the volume of the current sphere is:
 V2 = (4/3) * (pi) * ((1 + 2 * (1)) ^ 3)
 V2 = (4/3) * (pi) * ((1 + 2) ^ 3)
 V2 = (4/3) * (pi) * ((3) ^ 3)
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3 years ago
Read 2 more answers
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