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sdas [7]
3 years ago
10

How do I factor- EX 4x^2+7x - 15 = 0

Mathematics
1 answer:
Igoryamba3 years ago
8 0

Use the quadratic equation to solve this (bellow will be the image of the quadratic function)  

Remember that quadratic functions are set up like so:

ax^{2} +bx +c = 0

That means that in this equation...

a = 4

b = 7

c = -15

^^^Plug these numbers into the quadratic equation and solve...

\frac{-7+/-\sqrt{(7)^{2}-4(4)(-15)}}{2(4)}

\frac{-7 +/-\sqrt{49+240}}{8}

\frac{-7+/-\sqrt{289}}{8}

\frac{-7+/-17}{8}

Keep in mind that +/- is ±

\frac{-7+17}{8} ---> \frac{5}{4}

\frac{-7-17}{8} ---> -3

Take the opposite of those numbers^^^ like so

(x + 3)(4x - 5)

Hope this helped!

~Just a girl in love with Shawn Mendes

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cricket20 [7]
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UNO [17]

Answer:

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8 0
1 year ago
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kicyunya [14]

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Step-by-step explanation:

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4 0
3 years ago
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elena-s [515]
Actually, i think something is missing here:

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two:

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or more: so potentially all of them can be repeating, even a!

it could be: 1.(111114)

or: 1.111114111114111114111114111114111114111114111114111114111114111114111114111114...

proably B. is the most typical of repeating decimals (choosed this one if you have to), but in reality, you need more information... did you copy the question exactly?
7 0
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stich3 [128]
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The final answer is 49/(d+kf)~
6 0
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