Answer:
270725 different ways
Step-by-step explanation:
The problem tells us that the order of the letters does not matter. Therefore, in the combination the order is NOT important and is signed as follows:
C (n, r) = n! / r! (n - r)!
We have to n = 52 and r = 4
C (52, 4) = 52! / 4! * (52-4)! = 52! / (4! * 48!) = 270725
Which means that there are 270725 different ways in total to make that raffle
The correct answer is that the angles created are equal.
The steps given are used to create an angle bisector of the angle. That means it divides the angle into 2 congruent angles.
Sorry for the delay!
Let x = charge before tax in 1st city, and y = charge before tax in 2nd city
y = $1500 + x
4/100x => tax in first city
3.5/100y => tax in second city
0.04x + 0.035y = $408.75
We have the following system of equations to solve:
So the hotel charge before tax in city 1 = $4750, and the hotel charge before tax in city 2 = $6250
<h3>
Answer: x = 18 (choice B)</h3>
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Work Shown:
Through the inscribed angle theorem, we can say that 2 times the inscribed angle gets us the arc that the inscribed angle cuts off.
2*(inscribed angle) = arc measure
2*(2x+2) = 76
4x+4 = 76
4x+4-4 = 76-4 ... subtract 4 from both sides
4x = 72
4x/4 = 72/4 ... divide both sides by 4
x = 18
<u>Answer:</u>
The number of ways can you win first prize and your mom win second is 1/56 ways.
<u>Step-by-step explanation:</u>
Total number of people entered the contest= 8 people
Total number of prices awarded=3 prizes
Therefore the total number of ways in which 3 prizes can be awarded = 8*7*6 = 336 ways
The number of ways in which you can win first prize and your monm can win the second prize is =1*1*6 = 6 ways
So,by probability to find the ways with which you can win the first prize and mom can win the second prize can be calculated as = 6/336 = 1/56
